[英]Bumping version string using sed/regex/bash script
I am currently building a CI pipeline that handles incrementing version from a maven pom.xml
file. 我目前正在建立一个CI管道来处理来自maven
pom.xml
文件的递增版本。 The pom file looks something like this: pom文件如下所示:
<?xml version="1.0" encoding="UTF-8"?>
<project xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://maven.apache.org/POM/4.0.0"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>
<artifactId>myApp</artifactId>
<version>1.0.0-SNAPSHOT</version>
<parent>
<groupId>com.acme.project</groupId>
<artifactId>parentApp</artifactId>
<version>1.0.0-SNAPSHOT</version>
</parent>
<dependencies>
<!-- internal libs -->
<dependency>
<groupId>...
I want to perform the following: 我要执行以下操作:
1.0.0-SNAPSHOT
and replace it with 1.0.0
1.0.0-SNAPSHOT
并将其替换为1.0.0
1.0.1-SNAPSHOT
) 1.0.1-SNAPSHOT
) Since I am using Teamcity, I am limited to using bash/sed/regex for this string manipulation. 由于我使用的是Teamcity,因此仅限于使用bash / sed / regex进行此字符串操作。 For step 1 I have done something like this:
对于第1步,我做了如下操作:
sed -i -e '1,/<version>1.0.0-SNAPSHOT<\/version>/s/<version>1.0.0-SNAPSHOT<\/version>/<version>1.0.0<\/version>/' pom.xml
The problem is that I am hardcoding the version - this could be 1.0.2-SNAPSHOT
, so I need a way to extract this in a flexible way. 问题是我正在对版本进行硬编码-这可能是
1.0.2-SNAPSHOT
,所以我需要一种灵活的方式来提取它。 For step 2, I have no idea how to do it with a primitive tool like sed/regex. 对于第2步,我不知道如何使用sed / regex之类的原始工具来实现。
with bash and grep 与bash和grep
# extract the version
v=$(grep -m1 -o '[^<>]*-SNAPSHOT' pom.xml)
[[ $v ]] || { echo "failed to extract version"; exit 1;}
# bumped version remove -SNAPSHOT suffix
bv=${v%-SNAPSHOT}
# new version (split on last dot)
nv=${bv%.*}.$((${bv##*.}+1))
or driectly with perl 或与perl直接
perl -i -pe 's/([^<>]*)(\d+)-SNAPSHOT/$1.($2+1)/e' pom.xml
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