在字符串中拆分整数-Python

Question

I've got a bunch of numbers in a string. I want to split them into individual digits so I can do more with them later.

number = [6, 18, 6, 4, 12, 18, 0, 18]

I want to split these like so.... ex: 6, 1, 8, 6, 4, 1, 2, 1, 8, 0, 1, 8

I've tried split(), I've tried list(str(number)), I've tried converting these to strings and integers and I have tried searching stackoverflow.

In other searches I keep seeing a list comprehension example like this, which I don't understand and don't get the desired result after trying: [int(i) for i in str(number)]

help??

Answer 1

First you have to consider every element of the list as a string, and then cast back every character to an integer.

def customSplit(l):
        result = []
        for element in l:
                for char in str(element):
                        result.append(int(char))
        return result

print(customSplit([6, 18, 6, 4, 12, 18, 0, 18]))
# prints [6, 1, 8, 6, 4, 1, 2, 1, 8, 0, 1, 8]

Answer 2

How about a list comprehension :

[ digit for x in number for digit in str(x) ]

which produces a list of strings:

['6', '1', '8', '6', '4', '1', '2', '1', '8', '0', '1', '8']

or

[ int(digit) for x in number for digit in str(x) ]

if you'd prefer a list of single-digit integers:

[6, 1, 8, 6, 4, 1, 2, 1, 8, 0, 1, 8]

Answer 3

You can use itertools.chain like so:

>>> list(map(int, chain.from_iterable(map(str, numbers))))
[6, 1, 8, 6, 4, 1, 2, 1, 8, 0, 1, 8]

---

I posted this mainly so I could compare it to a Coconut equivalent:

>>> numbers |> map$(str) |> chain.from_iterable |> map$(int) |> list

while looks nicer. If you like Unicode characters, you can replace |> with ↦ :

>>> numbers ↦ map$(str) ↦ chain.from_iterable ↦ map$(int) ↦ list

In standard Python, a list comprehension is probably more readable.