如何访问或检查超级父级组件中子组件的模板驱动表单的验证

Question

Say i am having a set of components with the parent-child relationship. The the structure is as follows: [A]-->[B]-->[C]-->[D] (ie) A is the parent of B , B is the parent of C , C is the parent of D. I need to check the validity of template-driven form in component D from the component A . I have tried using @viewchild(). in my componentA.html

 <form #mainform ="ngform"> <button [disabled]= "componentB?.ComponentC?.ComponentD?.form?.invalid"> </button> </form> 

This approach is not working.

How can I achieve this from A to D without using event emitter?

Answer 1

It does not matter how deeply it is nested in the component tree. It matters how it is nested in the form tree.

Asumming the child controls are named child , grandchild and grandgrandchild you can do something like this:

<form #mainform="ngform">
  <button [disabled]="mainform.control.get('child.grandchild.grandgrandchild').invalid">
    </button>
</form>

We use the mainform.control to get the access to the underlying FormGroup . Now we have an access to all methods on the FormGroup class. You can see the full list here .

Next we use the get method to traverse the form tree and reach for the child control.

If you have a form tree like this:

mainform: {
  child: {
    grandchild: {
       grandChild
    }
  }
}

Where mainform , child , and grandchild are FromGroups and grandgrandchild is a FormControl`.

You can access the grandgrandchild by typing: mainForm.get('child.grandchild.grandchild')