如何使用另一列删除字符串的未使用部分

Question

How to remove unused part of string used value in another Pandas column?

I have:

Col1         Col2
bbbb2         Hello I want to removebbbb2

Output:
Hello I want to bbbb2

I want to use str.extract or any other pandas solution?

EDIT: @erocoar But i want to remove in all rows, For example

Col1        Col2                                           output
bbbb2     Hello I want to removebbbb2        Hello I want to bbbb2
aaaa1     Hello I want to remaaaa1           Hello I want to aaaa1

Your solution is only for one example

Answer 1

You could for example sub out all the characters other than bbbb2 .

df = pd.DataFrame(data={"Col1": ["bbbb2"], "Col2": ["Hello I want to removebbbb2"]})

df["Col2"].str.replace("(?:\S*)?(bbbb2)(?:\S*)?", "\\1")

Out[29]: 
0    Hello I want to bbbb2
Name: Col2, dtype: object

Edit: For multiple rows, eg

import re
df = pd.DataFrame(data={"Col1": ["bbbb2", "aaaa1"], "Col2": ["Hello I want to removebbbb2", "Hello I want to remaaaa1"]})
df["out"] = df.apply(lambda x: re.sub("(?:\S*)?(" + x[0] + ")(?:\S*)?", "\\1", x[1]), axis=1)

df
Out[127]: 
    Col1                         Col2                    out
0  bbbb2  Hello I want to removebbbb2  Hello I want to bbbb2
1  aaaa1     Hello I want to remaaaa1  Hello I want to aaaa1

Answer 2

Using .apply with lambda

Demo:

import pandas as pd

df = pd.DataFrame({"Col1":["bbbb2", "aaaa1"], "Col2":["Hello I want to removebbbb2", "Hello I want to remaaaa1"]})
def rep(row):
    s = row["Col2"].split()
    s[-1] = row["Col1"]
    return " ".join(s)

print(df.apply(lambda row: rep(row), axis=1))

Output:

0    Hello I want to bbbb2
1    Hello I want to aaaa1
dtype: object