Laravel获得最高预订酒店数量

Question

Having a hotel booking application and i need to get the 4 top booked hotels.

i have a relationship, to hotel in the Reservation.php

public function hotel(){
        return $this->belongsTo('App\Hotel');
    }

I can achieve what i wanted with the following query:

Reservation::select(DB::raw('*, COUNT(hotel_id) as hotel_count'))->with('hotel')->groupby('hotel_id')->orderby('hotel_count', 'desc')->limit(4)->get();

Is there any simplified version is available to the above query?

Update: Db structure

Answer 1

Reservation::withCount('hotel')->orderBy('hotel_count', 'desc')->take(4)->get();

看看https://laravel.com/docs/5.6/eloquent-relationships#counting-related-models

Answer 2

In your Hotel.php model

public function reservation()
{
    return $this->hasMany('App\Reservation');
}

In your controller you can access by

Hotel::withCount('reservation')->orderBy('reservation_count', 'desc')->limit(4)->get();