如何在不知道Arduino大小的情况下创建数组并在其中存储值

Question

I'm trying to write Arduino code for receiver that receives hexadecimal values from another Arduino (Transmitter), then I want to check this values and store them in new array which I don't know its size, while transmitter sends values receiver will store them.

Values reaches successfully to receiver but I don't know how to store them in new array.

My receiver code is like this:

for (i = 0; i < len; i++)
{
 if (receivedValue[i]==0x60)
          {
    //digitalWrite(LED1,LOW); 
    // store receivedValue[i] in the new array
          }
          else
          {
            if(receivedValue[i]==0x61)
            {
            //digitalWrite(LED3,LOW); 
             // store receivedValue[i] in the new array
            }

            if (receivedValue[i]==0x62)
            {
            //digitalWrite(LED4,LOW); 
              // store receivedValue[i] in the new array
          }

          // any other receivedValue[i] dont do anything
        }
    }

LEDs works successfully as I want but how to store them in array?

Answer 1

Two approaches suggested:

1. Array pre-defined with fixed size

    #define MAX_ITENS 50 // The size of buffer uint8_t buffer[MAX_ITENS]; // The Buffer uint8_t posBuffer = 0; // Pointer to actual position loop() { .... // Add data to buffer posBuffer++; if (posBuffer == MAX_ITENS) { // Buffer overflow - You can set position to 0 // or give some error } else { buffer[posBuffer] = data; // Save the data } } 

2. Use a dynamic array library I like this one .