[英]Parse json array and loop through all the data for Pivot.js
I have a json array data in this format:我有一个这种格式的 json 数组数据:
{
"jobs": [
{
"id": "some_random_id_1",
"email": "some@email.com",
"email_type": "html",
"status": "pending",
"job_fields": {
"TITLE": "job title here"
},
"stats": {
"applied": 40,
"rejected": 20
}
},
{
"id": "some_random_id_2",
"email": "some@email.com",
"email_type": "html",
"status": "pending",
"job_fields": {
"TITLE": "job title here"
},
"stats": {
"applied": 30,
"rejected": 20
}
},
{
"id": "some_random_id_3",
"email": "some@email.com",
"email_type": "html",
"status": "pending",
"job_fields": {
"TITLE": "job title here"
},
"stats": {
"applied": 13,
"rejected": 1
}
},
{
"id": "some_random_id_4",
"email": "some@email.com",
"email_type": "html",
"status": "pending",
"job_fields": {
"TITLE": "job title here"
},
"stats": {
"applied": 13,
"rejected": 1
}
}
],
"job_id": "some_id",
"total_jobs": 60
}
where I just need to access the jobs
object and grab id
and status
and all info for job_fields
and stats
(or all info for now).我只需要访问jobs
对象并获取id
和status
以及job_fields
和stats
所有信息(或现在的所有信息)。
// example is from here
// https://pivottable.js.org/examples/mps.html
$(function(){
$.getJSON("data.json", function(mps) {
$("#output").pivotUI(mps);
});
});
the example works with this json format:该示例适用于这种 json 格式:
[{
"Province": "Quebec",
"Party": "NDP",
"Age": 22,
"Name": "Liu, Laurin",
"Gender": "Female"
},
{
"Province": "Quebec",
"Party": "Bloc Quebecois",
"Age": 43,
"Name": "Mourani, Maria",
"Gender": "Female"
},
{
"Province": "Ontario",
"Party": "Conservative",
"Age": "",
"Name": "O'Toole, Erin",
"Gender": "Male"
}
]
I am not sure how to modify the javascript so it can read my json format.我不确定如何修改 javascript 以便它可以读取我的 json 格式。 I can't modify the json format to match the above format, so in the above javascript example, province, party, etc
are all passed to the function.我无法修改json格式来匹配上面的格式,所以在上面的javascript例子中, province, party, etc
都是传递给函数的。
I want to do the same but with my json format, so output id, status, all members of job_fields (ex: TITLE, etc. ), all members of stats (ex: applied, rejected
.我想用我的 json 格式做同样的事情,所以输出id, status, all members of job_fields (ex: TITLE, etc. ), all members of stats (ex: applied, rejected
.
Assuming all jobs have job_fields.TITLE, stats.applied and stats.rejected maybe the following will do:假设所有作业都有 job_fields.TITLE、stats.applied 和 stats.rejected 可能会执行以下操作:
const json = { "jobs": [ { "id": "some_random_id_1", "email": "some@email.com", "email_type": "html", "status": "pending", "job_fields": { "TITLE": "job title here" }, "stats": { "applied": 40, "rejected": 20 } }, { "id": "some_random_id_2", "email": "some@email.com", "email_type": "html", "status": "pending", "job_fields": { "TITLE": "job title here" }, "stats": { "applied": 30, "rejected": 20 } }, { "id": "some_random_id_3", "email": "some@email.com", "email_type": "html", "status": "pending", "job_fields": { "TITLE": "job title here" }, "stats": { "applied": 13, "rejected": 1 } }, { "id": "some_random_id_4", "email": "some@email.com", "email_type": "html", "status": "pending", "job_fields": { "TITLE": "job title here" }, "stats": { "applied": 13, "rejected": 1 } } ], "job_id": "some_id", "total_jobs": 60 }; console.log( json.jobs.map( (job)=>({ id:job.id, status:job.status, title:job.job_fields.TITLE, applied:job.stats.applied, rejected:job.stats.rejected }) ) );
Can try with below snippet:可以尝试使用以下代码段:
$(function(){
$.getJSON("data.json", function(orgData) {
var pivotData = [];
orgData.jobs.forEach(function (job, ind) {
var reqInfo = {};
reqInfo['id'] = job.id;
reqInfo['status'] = job.status;
reqInfo['jobTitle'] = job.job_fields && job.job_fields.TITLE;
reqInfo['applied'] = job.stats && job.stats.applied;
reqInfo['rejected'] = job.stats && job.stats.rejected;
pivotData.push(reqInfo)
})
$("#output").pivotUI(pivotData);
});
}); });
You can use map
and use Object.assign
and spread operator
to make an object您可以使用map
并使用Object.assign
和spread operator
来制作对象
var obj={"jobs":[{"id":"some_random_id_1","email":"some@email.com","email_type":"html","status":"pending","job_fields":{"TITLE":"job title here"},"stats":{"applied":40,"rejected":20}},{"id":"some_random_id_2","email":"some@email.com","email_type":"html","status":"pending","job_fields":{"TITLE":"job title here"},"stats":{"applied":30,"rejected":20}},{"id":"some_random_id_3","email":"some@email.com","email_type":"html","status":"pending","job_fields":{"TITLE":"job title here"},"stats":{"applied":13,"rejected":1}},{"id":"some_random_id_4","email":"some@email.com","email_type":"html","status":"pending","job_fields":{"TITLE":"job title here"},"stats":{"applied":13,"rejected":1}}],"job_id":"some_id","total_jobs":60} var result = obj.jobs.map(({id,status,job_fields,stats}) => { return Object.assign({}, {id}, {status}, {...job_fields}, {...stats}); }); console.log(result);
Or you can make it shorter like:或者你可以让它更短,比如:
var result = obj.jobs.map( ({id,status,job_fields,stats}) => Object.assign({},{id},{status},{...job_fields},{...stats}) );
$("#output").pivotUI(mps.jobs);
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