比较子字符串数组

Question

How can I check if an array of strings contains part of words stored in another array of strings ?

Let's say I've declared these three arrays :

array1 = ["Lorem", "ipsum", "dolor" "sit" "amet"]

array2 = ["Lorem", "ipsum"]

keywords = ["ipsum", "dol"]

When comparing array1 with keywords , I want to get something like true because "ipsum" and "dol" are in array1 , but false , when comparing array2 with keywords because "dol" isn't in array2

I searched for an hour, but I don't know how to do it... I succeeded to compare arrays with one keyword, but not with several keywords.

Answer 1

• For every element in keywords array (use .every() )
• There must be some element in other array (use .some() )
• That includes the string currently in consideration (use .includes() )

Demo:

 let array1 = ["Lorem", "ipsum", "dolor", "sit", "amet"], array2 = ["Lorem", "ipsum"], keywords = ["ipsum", "dol"]; let compare = (a, k) => k.every(s => a.some(v => v.includes(s))); console.log(compare(array1, keywords)); console.log(compare(array2, keywords)); 

Docs:

• Array.prototype.every()
• Array.prototype.some()
• String.prototype.includes()

Answer 2

您可以使用Array.every

let contains = keywords.every(k => array1.findIndex(a => a.indexOf(k) > -1) > -1)

Answer 3

function arrayContains(array1,array2){
 var res=0;
 for (var i=0;i<array1.length;i++){
  for (var j=0;i<array2.length;j++){
    if (array1[i]==array2[j])
        res++
   } 
 }
 return res==array2.length//if res is eqaul to array2.length then all elements of array2 are inside array1;
}

Answer 4

I would use indexOf instead of includes as includes do not work in IE browsers. Browser compatibility

 let array1 = ["Lorem", "ipsum", "dolor", "sit", "amet"], array2 = ["Lorem", "ipsum"], keywords = ["ipsum", "dol"]; let compare = (a, k) => k.every(s => a.some(v => v.indexOf(s) !== -1)); console.log(compare(array1, keywords)); console.log(compare(array2, keywords)); 

Answer 5

var array1 = ['a','b','c'];
var array2 = ['g','f','h'];

var keys = ['a','g'];

function checkIfExists(key, arr) {
   if (arr.indexOf(key) != -1) {
     console.log('Key ' + key + ' exists in array');
   } else {
     console.log('Key ' + key + ' does not exists in array');
   } 

}

for (var i = 0; i < keys.length; i++) {
    checkIfExists(keys[i], array1);
}

for (var i = 0; i < keys.length; i++) {
    checkIfExists(keys[i], array2);
}

Output :

Key a exists in array Key g does not exists in array Key a does not exists in array Key g exists in array