如何使用PHP创建具有当前日期的10位随机数

Question

I need to create 10 digit random number with current date and some input value using PHP. I am explaining my code below.

$current_date=date('Y-m-d');//2018-04-30
$user_input=1;

above data are the user input and my expected output should look below.

$output=1804300001

The random number generation format should be like this yymmdd with 4 digit number including user input . Suppose user_input=1 then it should be 0001 and user_input=12 then it should be 0012 like this.

Answer 1

Something like this

$date = new DateTime();
$input = 1;
$output = date_format($date,"ymd").sprintf('%04u', $input);

Answer 2

<?php

echo getToken(1);     #201804300001
echo getToken(9999);  #201804309999
echo getToken(12345); #201804301234


function getToken($input) {
    return date('Ymd').str_pad (substr($input, 0, 4) , 4, '0', STR_PAD_LEFT);
}

Answer 3

here some code for you...there many solutions.

$user = 12;
$date = date("ymd", $time());
echo $datum .sprintf("%04u",$user);

Best regards

Answer 4

If using your code ( $current_date=date('Ym-d'); //2018-04-30 ):

$current_date = date('Y-m-d');
$user_input = 1;
$result = substr(str_replace('-', '', $current_date), 2); // Replace "-" with nothing plus remove first 2 digits
$result .= str_pad($user_input, 4, '0', STR_PAD_LEFT); // Fill in with "0" to the left

Might not be the prettiest code but it works fine.