[英]Error: gunicorn: Failed to find application object 'app' in 'app'
Here's my code:这是我的代码:
app.py应用程序.py
from flask_graphql import GraphQLView
from app.infrastructure.graphql import schema
from app.infrastructure.api_resource import app
app.add_url_rule('/graphql', view_func=GraphQLView.as_view('graphql', schema=schema, graphiql=True))
if __name__ == '__main__':
app.run(debug=True)
api_resource.py api_resource.py
import app.infrastructure.repository as repository
from flask import request, url_for
from flask_restplus import Api, Resource, fields
from sqlalchemy_pagination import paginate
from sqlalchemy_fulltext import FullTextSearch
app = repository.app
api = Api(app, version='0.1', title='xxxxx',
description='xxxxx')
...
repository.py存储库.py
from flask import Flask
from flask_sqlalchemy import SQLAlchemy
from app.domain.model import Base
connection_string = 'xxxxxx'
app = Flask(__name__)
app.config['SQLALCHEMY_DATABASE_URI'] = connection_string
app.config['SQLALCHEMY_ECHO'] = True
db = SQLAlchemy(app, metadata=Base.metadata)
However, when i execute the gunicorn command "gunicorn app: app" i get this error:但是,当我执行 gunicorn 命令“gunicorn app: app”时,出现此错误:
Failed to find application object 'app' in 'app'
I'm using pipenv whith pipenv shell on ubuntu 16.04, but i've also tried on a docker container and got the same error.我在 ubuntu 16.04 上使用 pipenv whith pipenv shell,但我也尝试了 docker 容器并得到了同样的错误。 here's my pip file:这是我的 pip 文件:
[[source]]
url = "https://pypi.python.org/simple"
verify_ssl = true
name = "pypi"
[dev-packages]
[packages]
flask-graphql = "*"
flask-sqlalchemy = "*"
sqlalchemy-fulltext-search = "*"
graphene-sqlalchemy = ">=2.0"
flask-marshmallow = "*"
sqlalchemy-pagination = "*"
flask-restplus = "*"
requests = "*"
mysqlclient = "*"
gunicorn = "*"
[requires]
python_version = "3.6"
What am i doing wrong?我究竟做错了什么?
You have a folder called app
(as by the import lines in your file) and a app.py
file.您有一个名为app
的文件夹(如文件中的导入行)和一个app.py
文件。
Gunicorn will try to find the app
WSGI variable inside the app
module, which in your case is identified as app/__init__.py
Gunicorn 将尝试在app
模块中查找app
WSGI 变量,在您的情况下,该变量被标识为app/__init__.py
You need to rename your folder or your app.py
file to avoid this conflict.您需要重命名文件夹或app.py
文件以避免此冲突。
I found that this bug only happens on gunicorn version 20+.我发现这个错误只发生在 gunicorn 版本 20+ 上。 When I downgrade to version 19.9.0, it works fine even with the folder and app.py
sharing the same name.当我降级到版本 19.9.0 时,即使文件夹和app.py
共享相同的名称,它也能正常工作。
Accepted answers might be spot on for the original question , however I got the same error and I was running the gunicorn command as :接受的答案可能会出现在原始问题上,但是我遇到了同样的错误,并且我正在运行 gunicorn 命令:
gunicorn app
In my case neither renaming the app.py nor downgrading worked.在我的情况下,重命名 app.py 和降级都不起作用。
Following fixed the issue:以下修复了问题:
gunicorn app:app
After a lot of trial and error trying to change things in init files and the dockerfile, this is what we ended up with, in our gunicorn/conda/Docker stack:在尝试更改 init 文件和 dockerfile 中的内容的大量试验和错误之后,这就是我们在 gunicorn/conda/Docker 堆栈中的最终结果:
FROM continuumio/miniconda3
WORKDIR /app
# create environment
COPY environment.yml /app
RUN conda env create --name my_app_env --file environment.yml
# ensure RUN commands use the new environment
SHELL ["conda", "run", "-n", "my_app_env ", "/bin/bash", "-c"]
COPY . .
EXPOSE 8123
ENTRYPOINT [\
"conda", "run", "--no-capture-output", "-n", "my_app_env ",\
"gunicorn", "-b", "0.0.0.0:8123",\
"--pythonpath", "src/MyApp",\
"src.MyApp.app:server"\
]
MyApp
|- src
|- MyApp
- __init__.py (file is empty for now)
- app.py
- Dockerfile
- environment.yml
- setup.py
server = flask.Flask(__name__)
app = Dash(__name__, suppress_callback_exceptions=True, server=server)
)```
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