如何在Spring Boot XML文件中注册servlet？

Question

I wrote a servlet for a Spring Boot application. It worked when I used

contextHandler.addServlet(MyClass.class, "/v1/route");

Now I'm trying to register the servlet in beans.xml file as a bean. This one

<bean id="myId" class="com.abc.MyClass"/>

doesn't contain route. MyClass extends HttpServlet and overrides doGet method.

How to register a servlet which is also a bean?

Answer 1

This approach worked for me. It's a mix of declaration in XML and a fully programmatic registration.

In beans.xml file I've specified a constructor parameter which passed ServletContextHandler, like this:

<bean id="myId" class="com.abc.MyClass">
    <constructor-arg ref="servletContextHandler"/>
</bean>

In MyClass constructor I'm adding the servlet - together with route - to the servlet holder, thus registering it as servlet:

public MyClass(ServletContextHandler h) {
    h.addServlet(new ServletHolder(this), "/v1/route");
}

Surely this can interfere with other requirements, like the constructor may need other parameters, other initializations may be needed. But here I'm registering a bean in XML and registering servlet programmatically. May be the servlet registration can also be done without explicit Java code, I don't know how to do that.

xerx593, I've seen that page but those examples didn't look good enough for what I wanted. Thank you anyway.