Python：将具有多行的字典写入CSV

Question

I've got a dictionary with multiple rows from my question before. It's generated via:

import requests
from bs4 import BeautifulSoup
import re
import csv

links = ["34519-kevitsa-copper-concentrator-plant", "34520-kevitsa-copper-mine", "34356-glogow-copper-refinery"]

for l in links:

    page = requests.get("https://www.industryabout.com/country-territories-3/2199-finland/copper-mining/"+l)
    soup = BeautifulSoup(page.content, 'lxml')
    rows = soup.select("strong")
    d = {}

    for r in rows:
        name, value, *rest = r.text.split(":")
        if not rest:
            d[name] = value
    print(d)

print(d.items()) gives:

dict_items([('Commodities', ' Copper, Nickel, Gold'), ('Area', ' Lappi'), ('Type', ' Copper Concentrator Plant') ])

dict_items([('Commodities', ' Copper, Nickel, Gold'), ('Area', ' Lappi'), ('Type', ' Open-pit Mine') ])

dict_items([('Commodities', ' Copper'), ('Area', ' Dolnoslaskie'), ('Type', ' Copper Refinery') ])

But when I write this to CSV with any of the solutions from " Writing a dictionary to a csv file with one line for every 'key: value' " I only get the LAST dictionary item, the others are omitted.

Commodities;Copper
Area;Dolnoslaskie
Type;Copper Refinery

How can I write a CSV with looks like this:

Commodities;Area;Type
Copper, Nickel, Gold;Lappi;Copper Concentrator Plant
Copper, Nickel, Gold;Lappi;Open-pit mine
Copper;Dolnoslaskie;Copper Refinery

I've also tried to change to an array, but coulnd't find a solution for array[name] = value .

This answer seems perfect, but iterkeys is Python 2 only.

with open('my_data.csv', 'wb') as ofile:
    writer = csv.writer(ofile, delimiter='\t')
    writer.writerow(['ID', 'dict1', 'dict2', 'dict3'])
    for key in ddict.iterkeys():
        writer.writerow([key] + [d[key] for d in dicts])

Answer 1

import csv

with open('data.csv', 'w') as outfile:
    writer = csv.DictWriter(outfile, ['Commodities', 'Area', 'Type'], delimiter=';')
    writer.writeheader()
    for l in links:
        ...
        print(d)
        writer.writerow(d)

Answer 2

You can try this.

#!python
# -*- coding: utf-8 -*-#

d = {k:v for (k,v) in zip(list('abc'),range(3))}
print(d)

with open('a.txt','w') as fo:
    for i in d:
        line = '{};{}\n'.format(i,d[i])
        fo.write(line)