语法错误意外标记“>”

Question

I've been testing my JS code on different browsers but it doesn't seem to work on some of them and on mobile either.

JS

function req1() {
  fetch('https://jsonplaceholder.typicode.com/posts/1')
    .then(response => response.json())
    .then(json => {
      var title = json.title;
      var body = json.body; 
      document.getElementById("newsTitle").innerHTML = title;
      document.getElementById("newsContent").innerHTML = body;
      document.getElementById("newsContent2").innerHTML = body;
    });
}
req1();

By reading this question I understood that the problem could be related to '=>' because it is a ES6 element and not all the browsers support it. But as you can see here it seems to be the way to get those json data: https://jsonplaceholder.typicode.com/

Is there a way to avoid using '=>' in this function to make it work on all the browsers?

Here the error that I get on Safari 9 for example:

I tried some solutions but now I get this error:

posts are not printed yet, any idea?

Answer 1

Just use normal function syntax instead of ES6 arrow-syntax:

function req1() {
  fetch('https://jsonplaceholder.typicode.com/posts/1')
    .then(function (res) {return res.json()})
    .then(function (json) {
      var title = json.title;
      var body = json.body; 
      document.getElementById("newsTitle").innerHTML = title;
      document.getElementById("newsContent").innerHTML = body;
      document.getElementById("newsContent2").innerHTML = body;
    });
}
req1();

Most browsers that don't support ES6 arrow-syntax are unlikely to support the Fetch API. For those I would suggest using another form of HTTP request, or using a Polyfill, like GitHub's

Answer 2

Use a normal function instead of a lambda:

"use strict";

function req1() {
    fetch('https://jsonplaceholder.typicode.com/posts/1').then(function(response){
        return response.json();
    }).then(function(json){
        var title = json.title;
        var body = json.body;
        document.getElementById("newsTitle").innerHTML = title;
        document.getElementById("newsContent").innerHTML = body;
        document.getElementById("newsContent2").innerHTML = body;
    });
}
req1();

---

Just write

.then(function(json){

Instead of

.then(response => response.json())

---

Also, if you're not sure about the ES6 Syntax in your script, you can use something like babel :

https://babeljs.io/repl/

Answer 3

you need use fetch polyfill and old function syntax not the new arrow function syntax of es6.

 function req1() { fetch('https://jsonplaceholder.typicode.com/posts/1') .then(function (res) {return res.json()}) .then(function (json) { var title = json.title; var body = json.body; document.getElementById("newsTitle").innerHTML = title; document.getElementById("newsContent").innerHTML = body; }); } req1(); 

 <script src="https://cdnjs.cloudflare.com/ajax/libs/fetch/2.0.4/fetch.js"></script> <div id="newsTitle"></div> <div id="newsContent"> </div> 

Browser Support For Fetch API polyfill

• Chrome
• Firefox
• Safari 6.1+
• Internet Explorer 10+

Answer 4

Change the following lines

then(response => response.json())

To

.then(function(response){ response.json() })

And

.then(json => {

To

.then(function (json) {

Full Code:

function req1() {
  fetch('https://jsonplaceholder.typicode.com/posts/1')
   .then(function(response){ response.json()})
   .then(function (json){
     var title = json.title;
     var body = json.body; 
     document.getElementById("newsTitle").innerHTML = title;
     document.getElementById("newsContent").innerHTML = body;
     document.getElementById("newsContent2").innerHTML = body;
   });
}
req1();

Answer 5

Why not to use a simple request

 var xhReq = new XMLHttpRequest();
 xhReq.open("GET", "https://jsonplaceholder.typicode.com/posts/1", false);
 xhReq.send(null);
 var serverResponse = xhReq.responseText;
 var json = JSON.parse(serverResponse);
 alert(json.title);