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节点js中的唯一json数据对象

[英]unique json data object in node js

i have a json data like this, 我有一个像这样的json数据,

var data = [ { _id: 5abb46b060808f3a2096f91d,
    patient_name: 'krishnaaaannnn',
    gender: 'male',
    charge_id: 5ab243ac73959deb3ad79fec,
    description: 'suffering from pain',
    hospital_id: 5aa92df9ec6b3cc78ff88afe,
    doctor_id: 5af142f879f06c22f5359be3 },
  { _id: 5af143a779f06c22f5359be4,
    patient_name: 'Rajesh',
    gender: 'male',
    description: 'suffering from fever',
    charge_id: 5aaa628e9ae2a2a642b7495c,
    hospital_id: 5aa92df9ec6b3cc78ff88afe,
    doctor_id: 5af142f879f06c22f5359be3 },
  { _id: 5af144685f2f292b2cc3af6d,
    patient_name: 'krishh',
    gender: 'male',
    description: 'suffering from fever',
    charge_id: 5aaa628e9ae2a2a642b7495c,
    hospital_id: 5aa92df9ec6b3cc78ff88afe,
    doctor_id: 5af142f879f06c22f5359be3 },
  { _id: 5abb46b060808f3a2096f91d,
    patient_name: 'krishnaaaannnn',
    gender: 'male',
    charge_id: 5ab243ac73959deb3ad79fec,
    description: 'suffering from pain',
    hospital_id: 5aa92df9ec6b3cc78ff88afe,
    doctor_id: 5af142f879f06c22f5359be3 } ]

where _id: 5abb46b060808f3a2096f91d is repeated twice, but i want this data object to be contain unique _id , please help me to solve 其中_id: 5abb46b060808f3a2096f91d重复了两次,但我希望此数据对象包含unique _id ,请帮助我解决

update: 更新:

This is my API to get this data from db, im just getting data from same collection twice, and now i want to make that final json as unique(_id) 这是我从db获取数据的API ,我只是两次从同一个集合中获取数据,现在我要使最终的json为unique(_id)

function billing_read_all(req, res) {
    var auth_data = res.locals.result;
    var searchParam = { token: auth_data[0].token }
    model.find("doctor", searchParam, function (doctor_data) {
        var searchParam1 = { doctor_id: doctor_data[0]._id }
        model.find("patient", searchParam1, function (patient_data) {
            var searchParam2={charge_id:ObjectId("5ab243ac73959deb3ad79fec")}
            model.find("patient", searchParam2, function (patient_data2) {
                var data = patient_data.concat(patient_data2)
                console.log(_.uniq(data))
                res.send(_.uniq(data))
            // res.send(patient_data)
            })
        })
    })
}

You can use a Map object for this purpose: 您可以为此使用Map对象:

var data = [ { _id: '5abb46b060808f3a2096f91d',
    patient_name: 'krishnaaaannnn',
    gender: 'male',
    charge_id: '5ab243ac73959deb3ad79fec',
    description: 'suffering from pain',
    hospital_id: '5aa92df9ec6b3cc78ff88afe',
    doctor_id: '5af142f879f06c22f5359be3' },
  { _id: '5af143a779f06c22f5359be4',
    patient_name: 'Rajesh',
    gender: 'male',
    description: 'suffering from fever',
    charge_id: '5aaa628e9ae2a2a642b7495c',
    hospital_id: '5aa92df9ec6b3cc78ff88afe',
    doctor_id: '5af142f879f06c22f5359be3' },
  { _id: '5af144685f2f292b2cc3af6d',
    patient_name: 'krishh',
    gender: 'male',
    description: 'suffering from fever',
    charge_id: '5aaa628e9ae2a2a642b7495c',
    hospital_id: '5aa92df9ec6b3cc78ff88afe',
    doctor_id: '5af142f879f06c22f5359be3' },
  { _id: '5abb46b060808f3a2096f91d',
    patient_name: 'krishnaaaannnn',
    gender: 'male',
    charge_id: '5ab243ac73959deb3ad79fec',
    description: 'suffering from pain',
    hospital_id: '5aa92df9ec6b3cc78ff88afe',
    doctor_id: '5af142f879f06c22f5359be3' } ];


var patientMap = new Map();

data.forEach(row => {
    if (!patientMap.has(row._id.toString())) patientMap.set(row._id.toString(), row);
});

// One entry per unique ID now
for (var value of patientMap.values()) {
  console.log(value);
};

Or enumerate: 或列举:

patientMap.forEach((row) => {
    console.log(row);
});

And to turn it back into an Array: 并将其转换回数组:

let newArray = [...patientMap.values()]
console.log(newArray);

You can use array#reduce with Object.values() to group your data based on _id . 您可以将array#reduceObject.values()以根据_id对数据进行分组。

 var data = [ { _id: '5abb46b060808f3a2096f91d', patient_name: 'krishnaaaannnn', gender: 'male', charge_id: '5ab243ac73959deb3ad79fec', description: 'suffering from pain', hospital_id: '5aa92df9ec6b3cc78ff88afe', doctor_id: '5af142f879f06c22f5359be3' }, { _id:'5af143a779f06c22f5359be4', patient_name: 'Rajesh', gender: 'male', description: 'suffering from fever', charge_id: '5aaa628e9ae2a2a642b7495c', hospital_id: '5aa92df9ec6b3cc78ff88afe', doctor_id: '5af142f879f06c22f5359be3' }, { _id: '5af144685f2f292b2cc3af6d',patient_name: 'krishh', gender: 'male', description: 'suffering from fever', charge_id: '5aaa628e9ae2a2a642b7495c', hospital_id: '5aa92df9ec6b3cc78ff88afe', doctor_id: '5af142f879f06c22f5359be3' }, { _id: '5abb46b060808f3a2096f91d', patient_name: 'krishnaaaannnn',gender: 'male', charge_id: '5ab243ac73959deb3ad79fec', description: 'suffering from pain', hospital_id: '5aa92df9ec6b3cc78ff88afe', doctor_id: '5af142f879f06c22f5359be3' } ], result = Object.values(data.reduce((r,o) => { r[o._id] = r[o._id] || {...o}; return r; },{})); console.log(result); 

ES5 code ES5代码

 'use strict'; var _extends = Object.assign || function (target) { for (var i = 1; i < arguments.length; i++) { var source = arguments[i]; for (var key in source) { if (Object.prototype.hasOwnProperty.call(source, key)) { target[key] = source[key]; } } } return target; }; var data = [{ _id: '5abb46b060808f3a2096f91d', patient_name: 'krishnaaaannnn', gender: 'male', charge_id: '5ab243ac73959deb3ad79fec', description: 'suffering from pain', hospital_id: '5aa92df9ec6b3cc78ff88afe', doctor_id: '5af142f879f06c22f5359be3' }, { _id: '5af143a779f06c22f5359be4', patient_name: 'Rajesh', gender: 'male', description: 'suffering from fever', charge_id: '5aaa628e9ae2a2a642b7495c', hospital_id: '5aa92df9ec6b3cc78ff88afe', doctor_id: '5af142f879f06c22f5359be3' }, { _id: '5af144685f2f292b2cc3af6d', patient_name: 'krishh', gender: 'male', description: 'suffering from fever', charge_id: '5aaa628e9ae2a2a642b7495c', hospital_id: '5aa92df9ec6b3cc78ff88afe', doctor_id: '5af142f879f06c22f5359be3' }, { _id: '5abb46b060808f3a2096f91d', patient_name: 'krishnaaaannnn', gender: 'male', charge_id: '5ab243ac73959deb3ad79fec', description: 'suffering from pain', hospital_id: '5aa92df9ec6b3cc78ff88afe', doctor_id: '5af142f879f06c22f5359be3' }], result = Object.values(data.reduce(function (r, o) { r[o._id] = r[o._id] || _extends({}, o); return r; }, {})); console.log(result); 

If you use a library like underscore.js it becomes a one-line solution, see snippet below. 如果您使用诸如underscore.js之类的库,它将成为单行解决方案,请参见下面的代码段。 You basically tell underscore to return a new array containing only the unique items, with unique criteria being the _id. 您基本上告诉下划线返回一个仅包含唯一项的新数组,唯一条件是_id。

 var data = [ { _id: '5abb46b060808f3a2096f91d', patient_name: 'krishnaaaannnn', gender: 'male', charge_id: '5ab243ac73959deb3ad79fec', description: 'suffering from pain', hospital_id: '5aa92df9ec6b3cc78ff88afe', doctor_id: '5af142f879f06c22f5359be3' }, { _id: '5af143a779f06c22f5359be4', patient_name: 'Rajesh', gender: 'male', description: 'suffering from fever', charge_id: '5aaa628e9ae2a2a642b7495c', hospital_id: '5aa92df9ec6b3cc78ff88afe', doctor_id: '5af142f879f06c22f5359be3' }, { _id: '5af144685f2f292b2cc3af6d', patient_name: 'krishh', gender: 'male', description: 'suffering from fever', charge_id: '5aaa628e9ae2a2a642b7495c', hospital_id: '5aa92df9ec6b3cc78ff88afe', doctor_id: '5af142f879f06c22f5359be3' }, { _id: '5abb46b060808f3a2096f91d', patient_name: 'krishnaaaannnn', gender: 'male', charge_id: '5ab243ac73959deb3ad79fec', description: 'suffering from pain', hospital_id: '5aa92df9ec6b3cc78ff88afe', doctor_id: '5af142f879f06c22f5359be3' } ]; var filteredData = _.uniq(data, (item) => item._id); console.log(filteredData); 
 <script src="http://underscorejs.org/underscore-min.js"></script> 

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