Python 3.6v range（）函数将无法执行

Question

def fn():
  theList = []
  for rev in range(5, 0, -1):
    theList.append(rev)
    print(theList)

fn()

I don't understand, why this won't execute? My goal is to print something like this

[5,4,3,2,1,0]
[4,3,2,1,0]
[3,2,1,0]
[2,1,0]
[1,0]
[0]

Edit 1. Okey i added the comma(,) but the result is this

[5]
[5, 4]
[5, 4, 3]
[5, 4, 3, 2]
[5, 4, 3, 2, 1]

Which is not what i am looking for

Answer 1

1)There is a typo in your function:

for rev in range(5, 0, -1):

2) you need to use your rev:

for rev in range(5, -1, -1):
    print(range(rev,-1,-1))

Answer 2

You can get your output like this:

def fn():
    theList = list(range(5, -1, -1))
    for idx in range(len(theList)):
        print(theList[idx:])
fn()

Output:

[5, 4, 3, 2, 1, 0]
[4, 3, 2, 1, 0]
[3, 2, 1, 0]
[2, 1, 0]
[1, 0]
[0]

Your code is using the wrong approach. Basically, your output shows that the list is full initially and goes on popping one element from the left on each iteration. Your approach starts with an empty list and adds an element on each iteration.

Also, range(5, 0, -1) is not the list you think it is. This is because the range function ignores the end value which is 0 here.

If you did this list(range(5, 0, -1)) , you'd get [5, 4, 3, 2, 1] which obviously doesn't contain 0. So, to get the list you want, you'd have to do list(range(5, -1, -1)) like in the code above.