正则表达式在PHP中替换为在一些前缀后得到数字或范围

Question

I have some texts with reference to lawsuit pages (folhas "fl. or fls." in portuguese) that I need to replace those numbers for a link (tag a) with an URL like:

"localhost/mni/consultarFolhas/".$page_start."/".$page_end

Text examples:

• [...] Fl. 53 : Considerando a manifestação do Estado, excluam-se os executados [...]
• [...] Nos termos das FLS 10/ 44 estão [...]
• [...] Ao ERJ para se manifestar objetivamente sobre fls. 88/92 [...]
• Às partes sobre resposta dos ofícios de fls. 320/325 e fls. 327/333 .
• [...] observadas as verbas que constam do documento fls. 61 do [...]
• Documento de Atualização de Pensão (DAP) apresentado às fls.61 , após sua contestação

As you can see some times they use plural (s) even for single pages but for multiple pages they normally use "/" to the separate the range.

I tried this Regex but it is still ineficiente to catch the situations described above:

const REGEX_FOLHAS = '#^.*\bfls?\. (\d+).*$#m';

So is it possible to create a REGEX to get those situations and replace with a hyperlink like this?

Nos termos das <a href='localhost/m-n-i/consultarFolhas/10/44/'> FLS 10/ 44 </a> estão

<a href='localhost/m-n-i/consultarFolhas/53/'>Fl. 53</a>: Considerando a manifestação do Estado, excluam-se os executados

Answer 1

Your regex is almost what you want but you forgot some patterns and modifiers:

• Remove anchors and greedy dots ( m flag too)
• Enable case-insensitivity ( i flag)
• Make \\. and following space characters optional: \\.? * \\.? *
• Write an optional pattern for slash separated digits (?:\\/ *\\d+)?
• Use capturing groups to extract data

Putting all together:

(?i)\bfls?\.? *(\d+)(?:(/) *(\d+))?

Live demo

PHP code:

preg_replace('~(?i)\bfls?\.? *(\d+)(?:(/) *(\d+))?~', '<a href="localhost/m-n-i/consultarFolhas/$1$2$3">$0</a>');