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数组的Java代码跟踪

[英]Java Code Tracing of Arrays

I'm having trouble with this school work, you have to trace the code of this array using a tracing table, however I am stuck for an answer. 我在这项功课上遇到了麻烦,您必须使用跟踪表来跟踪此数组的代码,但是我一直在寻找答案。

When I go through the code I get to the line where data[i] is given the index position of 0, which is 50 . 当我遍历代码时,到达data[i]的索引位置为0,即50 I then get confused as to if the table stops on that line because it cannot proceed because of data[i] is not less than data.length . 然后,我对表是否在该行上停止感到困惑,因为由于data[i]不小于data.length导致它无法继续进行。 So does it end there or am I wrong? 到此为止还是我错了?

public static int ???(int[] data) {

    int result = 1000;

    for (int i = 0; i < data.length; i++) {
        if (data[i] < result) {
            result = data[i];
        }
    }

    return result;
}

and the data is 数据是

{ 50, 43, 22, 30 } {50,43,22,30}

After the test, what do you think below line of code do? 测试之后,您如何看待下面的代码行?

result = data[i]; 结果=数据[i];

for (int i = 0; i < data.length; i++)

您将idata.length进行比较,而不将data[i]data.length进行比较,以便您的循环按预期运行(即,不会以i = 0结束)

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