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运行的jar中来自classpath目录的文件列表

[英]File list from classpath directory in running jar

I want to load all resource bundle properties from classpath, so that I can show supported languages. 我想从类路径中加载所有资源包属性,以便可以显示支持的语言。 I got a reference from here and tried 1st solution. 我从这里获得了参考,并尝试了第一种解决方案。 It works file when I run my code from eclipse. 当我从Eclipse运行代码时,它可以工作。 But when I create executable jar file, it could not read files. 但是,当我创建可执行jar文件时,它无法读取文件。 I don't know why behavior is different while running from command java -jar AppName.jar 我不知道为什么从命令java -jar AppName.jar运行时行为会有所不同

My Code Is: 我的代码是:

public static List<String> getResourceFiles(String path) throws IOException
{
    List<String> filenames = new ArrayList<>();

    InputStream in = getResourceAsStream(path);
    BufferedReader br = new BufferedReader(new InputStreamReader(in));
    System.out.println("br = " + br.readLine());
    String resource;
    while ((resource = br.readLine()) != null)
    {
        filenames.add(resource);
    }

    return filenames;
}

private static InputStream getResourceAsStream(String resource)
{
    final InputStream in = getContextClassLoader().getResourceAsStream(resource);
    System.out.println("input stream = " + in);

    return in == null ? FileUtil.class.getResourceAsStream(resource) : in;
}

private static ClassLoader getContextClassLoader()
{
    return Thread.currentThread().getContextClassLoader();
}

Here I noticed that InputStream is null when I run from command, but while running from eclipse InputStream is not null. 在这里,我注意到从命令运行时InputStream为null,但是从Eclipse运行时InputStream不为null。

How to solve this problem so that I can read resource files when running from command also? 如何解决此问题,以便从命令运行时也可以读取资源文件?

I found solution. 我找到了解决方案。 Below code worked for me: 下面的代码为我工作:

public static String[] getResourceListing(Class clazz, String path) throws URISyntaxException, IOException
{
    URL dirURL = clazz.getClassLoader().getResource(path);
    if (dirURL != null && dirURL.getProtocol().equals("file"))
    {
        /* A file path: easy enough */
        return new File(dirURL.toURI()).list();
    }

    if (dirURL == null)
    {
        /*
         * In case of a jar file, we can't actually find a directory. Have to assume the
         * same jar as clazz.
         */
        String me = clazz.getName().replace(".", "/") + ".class";
        dirURL = clazz.getClassLoader().getResource(me);
    }

    if (dirURL.getProtocol().equals("jar"))
    {
        /* A JAR path */
        String jarPath = dirURL.getPath().substring(5, dirURL.getPath().indexOf("!")); // strip out only the JAR file
        JarFile jar = new JarFile(URLDecoder.decode(jarPath, "UTF-8"));
        Enumeration<JarEntry> entries = jar.entries(); // gives ALL entries in jar
        Set<String> result = new HashSet<String>(); // avoid duplicates in case it is a subdirectory
        while (entries.hasMoreElements())
        {
            String name = entries.nextElement().getName();
            if (name.startsWith(path))
            { // filter according to the path
                String entry = name.substring(path.length());
                int checkSubdir = entry.indexOf("/");
                if (checkSubdir >= 0)
                {
                    // if it is a subdirectory, we just return the directory name
                    entry = entry.substring(0, checkSubdir);
                }
                result.add(entry);
            }
        }
        return result.toArray(new String[result.size()]);
    }

    throw new UnsupportedOperationException("Cannot list files for URL " + dirURL);
}

我认为您可以将应用程序路径添加到系统环境(类路径),如果无法解决问题,请在初始化文件流并修复它之前尝试打印真实路径。

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