如何使用Windows批处理文件一个一启动Spring Boot jar文件？

Question

I would like to start spring boot jar files one by one using windows batch file. I have created a batch file like below:

start java -jar service1.jar --spring.profiles.active=local
start java -jar service2.jar --spring.profiles.active=local 

When I ran this batch file, both jar files are running at once. But I have to run service1.jar file first and once its up and running then I need to run service2.jar file.

Can anyone please help me with this or any other way ?

Answer 1

Using start in a batch file doesn't wait for the process - it is kind of like starting a new thread.

There is another function call (or start /wait ) but these will work if it wasn't services. The problem you have is that the services need to keep running (you can't wait for them to finish with start /wait).

So you need to implement some kind of condition and a check in your batch file which when true to start service 2. For example if that's a web service and has a get method that can be used to check if it is working - call that method and wait for the result before starting the second service.

You can do something like:

start java -jar service1.jar --spring.profiles.active=local

:isStarted

set ready=false // Here you implement some logic to check if the service is running

if %ready%=="false" goto isStarted

start java -jar service2.jar --spring.profiles.active=local

Another solution would be to make a separate java program that tests service1 and exits when it is up and running. If we call it "service1test" then your bat file will be:

start java -jar service1.jar --spring.profiles.active=local
service1test   - without using start so it can wait
start java -jar service2.jar --spring.profiles.active=local

Answer 2

A very simple solution would be starting first service in a new command process (in background) , wait for example two seconds and then start second service also in a new command process (in background) before exiting current command process.

@echo off
start "Service 1" /B java.exe -jar service1.jar --spring.profiles.active=local
%SystemRoot%\System32\timeout.exe /T 2 /NOBREAK >nul
start "Service 2" /B java.exe -jar service2.jar --spring.profiles.active=local

For understanding the used commands and how they work, open a command prompt window, execute there the following commands, and read entirely all help pages displayed for each command very carefully.

• echo /?
• start /?
• timeout /?