打印单个拆分字符串

Question

The following code takes a string such as abcd#1234, removes the '#' and splits it into abcd and 1234

import sys
import re

print("User ID: {0}").format(sys.argv[1])
print("User Type: {0}").format(sys.argv[2])

sub = re.sub('[#]', '', sys.argv[1])
split = re.match(r"([a-z]+)([0-9]+)", sub, re.I)
print(split.groups())

The output from print(split.groups()) is <'abcd', '1234'> How can I take an individual section of the split such as abcd and just output that?

Answer 1

split.group(1) # --> 'abcd'
split.group(2) # --> '1234'

https://docs.python.org/3/library/re.html#re.match.group

Answer 2

Use index.

Ex:

s = "abcd#1234"
import re
sub = re.sub('[#]', '', s)
split = re.match(r"([a-z]+)([0-9]+)", sub, re.I)
print(split.groups()[0])
print(split.groups()[1])

Output:

abcd
1234

Answer 3

You can simply get the values of each as shown below:

data = split.groups()
if len(data) == 2:
    name, id = data
    print(name, id)

Or you can use group([group1, ...]) .

Answer 4

You can also use split directly and get just tell it to take the second element.

import sys
import re

string="abcd#1234"
string1=string.split("#")[1]  # tells it to take the second element of the split

print(string1) # Prints 1234