Struts 1-通过一个帖子调用更多操作，而无需更改struts-config

Question

I'm working on a legacy app (struts 1, own framework, java 6, on WebSphere 7) where I need to change the behavior of an operation.

Let's call them (1) CopyItem , (2) AlterItem , (3) MarkAsCopied .

A button called one service which needs to be replaced with three other services.
Depending on the result of the first one, invoke the second one and so on. I want to navigate in the end where the first one would take me (so it would look like the original behavior from user point of view).

Initially I thought I wrap every parameter I need into a form, POST it, and then on the Java side, I would call action execute for each service. Technically from CopyItemAction.execute() of CopyItem I would call AlterItem and MarkAsCopied executes as well.

I feel that this is pretty far from a clean solution.

Do you have a better idea, how to do this?

Answer 1

In the end I did it via synchronized Ajax. Which is definitely bad practice, so I do not recommend if you have the access on the backend code. However in my case now it turned out to be a working not-that-ugly solution. Based on Dave Newton's ( https://stackoverflow.com/users/438992/dave-newton ) proposal.
Keep that in mind the struts actions are still called according to the configuration defined in struts-config.xml.

I created the js function below and invoked the services with the specified forms one by one. This way a form (POST) submit calls the struts action, but doesn't navigate away. After they run successfully I redirected the page.

    function submitForm(form) {
        if (form !== null && form !== undefined) {

            let formData = new FormData(form);
            let xhr = new XMLHttpRequest();
            xhr.open('POST', form.getAttribute('action'), false);

            var successResponse = false;
            xhr.onreadystatechange = function() {
                if(xhr.readyState == XMLHttpRequest.DONE) {
                    successResponse = xhr.status == 200;
                }
            }

            xhr.send(formData);
            return successResponse;
        }
    }

In conclusion: this is not a recommended solution, but if you're in such a situation like me, then it works.