SQL查询查找和修剪

Question

I have a URL (example: https://mycompoany.com/data/test ) and want to remove everything left of test. What is the best way to do this?

I was going to use like the following. However, I'm not sure how to return the length of the last /.

LEN(LTRIM(THE_TEXT))

Answer 1

You can use SUBSTRING_INDEX() with -1 for the counter argument like this:

SUBSTRING_INDEX(THE_TEXT, '/', -1)

For example, this line:

SELECT SUBSTRING_INDEX('https://mycompoany.com/data/test', '/', -1)

returns test .

Answer 2

Thank you everyone for the assistance. It is greatly appreciated. Here is what I ended up doing.

SELECT top 10 profile_url,
    CASE
        WHEN CHARINDEX('/', profile_url) > 0 THEN
            RIGHT(profile_url, CHARINDEX('/', REVERSE(profile_url))-1)
        ELSE profile_url
    END
FROM connections