[英]Calculating IP checksum in C
I looked at RFC 1071 for some information on calculating the IP checksum. 我查看了RFC 1071 ,了解有关计算IP校验和的一些信息。 For the application I'm making, I need to calculate the IP checksum of a 20 byte IP header (no options).
对于我正在制作的应用程序,我需要计算20字节IP标头的IP校验和(无选项)。 My code is as follows:
我的代码如下:
uint16_t calculate_ip_chksum(IP *ip)
{
uint16_t *buf = (uint16_t *) ip;
uint32_t sum = 0;
uint16_t checksum = 0;
int counter = (ip->version & 0xF) * 4;
while (counter > 1)
{
sum += *buf++;
counter -= 2;
}
if (counter == 1)
sum += * (uint8_t *) buf;
while (sum >> 16)
sum = (sum & 0xFFFF) + (sum >> 16);
checksum = ~sum;
return checksum;
}
I defined an IP header as follows: 我定义了一个IP标头,如下所示:
typedef struct ip_h
{
uint8_t version;
uint8_t tos;
uint16_t tot_len;
uint16_t id;
uint16_t frag_off;
uint8_t ttl;
uint8_t proto;
uint16_t chksum;
uint32_t src;
uint32_t dst;
} IP;
I understand the mathematics of how to calculate the checksum, but I do not understand why my code (which is almost exactly the same as the RFC) does not work. 我了解如何计算校验和的数学方法,但是我不明白为什么我的代码(与RFC几乎完全相同)为什么不起作用。
You derive counter from ip->version instead of tot_len. 您从ip-> version而不是tot_len派生计数器。
int counter = (ip->version & 0xF) * 4;
I assume that you want total number of bytes in the buffer for checksum. 我假设您想要缓冲区中的总字节数作为校验和。
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