[英]SQLHANDLE-Parameters: function does not take x arguments (but it does, actually)
I implemented some function in c++ to handle sql-queries and stuff. 我在c ++中实现了一些功能来处理sql查询和其他内容。 Because I am doing this in different functions using the same handles, I am giving the handles as parameters (actually I want to inout references to the handles - but I am new to c++ and still having trouble understanding the concepts behind pointers and so).
因为我使用相同的句柄在不同的函数中执行此操作,所以我将句柄作为参数提供(实际上,我想输入对句柄的引用-但我对c ++还是陌生的,但仍然难以理解指针等的概念)。
Because the Error-Message is saying, that there is no function with x parameters, but there actually is one (there is a forward declaration as well), I think, that the definition and the use I am trying to make of it are somehow wrong. 因为错误消息说的是,没有带x参数的函数,但实际上有一个(还有一个前向声明),我认为我试图使用的定义和用法都在某种程度上错误。
Here is the forward declaration: 这是前向声明:
static HRESULT
_OpenDatabase(
LPCWSTR connectionString,
SQLHANDLE hdlStmt,
SQLHANDLE hdlEnv,
SQLHANDLE hdlConn
);
And the call (getting the connection string as input: __in LPCWSTR ConnectString) 和调用(获取连接字符串作为输入:__in LPCWSTR ConnectString)
SQLHANDLE hdlStmt = INVALID_HANDLE_VALUE;
SQLHANDLE hdlEnv = INVALID_HANDLE_VALUE;
SQLHANDLE hdlConn = INVALID_HANDLE_VALUE;
hr = _OpenDatabase(
ConnectString,
&hdlStmt, // this might be wrong?
&hdlEnv, // and this
&hdlConn // and this
);
What am I doing wrong? 我究竟做错了什么?
You're putting &
in front of the arguments. 您将
&
放在论据的前面。 Why? 为什么? You have 3
SQLHANDLE
, you need 3 SQLHANDLE
. 您有3个
SQLHANDLE
,您需要3个SQLHANDLE
。
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