使用 Bash 在给定的特定数字范围内生成随机浮点数

Question

can someone help me in generating random float number with given specific range of number in bash (shell). I found below command but is their any other option ? (using awk or $rand commands.)

jot -p2  0 1

Answer 1

If you have GNU coreutils available, you could go with:

seq 0 .01 1 | shuf | head -n1

Where 0 is the start (inclusive), .01 is the increment, and 1 is the end (inclusive).

Answer 2

Without any external utilities, generate random real between 3 and 16.999:

a=3
b=17
echo "$((a+RANDOM%(b-a))).$((RANDOM%999))"

Answer 3

To generate 1 random floating point number between 3 and 17:

$ awk -v min=3 -v max=17 'BEGIN{srand(); print min+rand()*(max-min+1)}'
16.4038

To generate 5 random floating point numbers between 3 and 17:

$ awk -v min=3 -v max=17 -v num=5 'BEGIN{srand(); for (i=1;i<=num;i++) print min+rand()*(max-min+1)}'
15.1067
4.79238
3.04884
11.3647
15.1132

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