[英]Prolog print numbers from 1 to N?
Assume the user gives an input N to the function, how would I print these numbers from 1 to N (recursively or other wise). 假设用户为该函数提供了输入N,我将如何打印这些数字(从1到N)(递归或其他方式)。
example 例
print_numbers(40). print_numbers(40)。
->1 - > 1
->2 - > 2
->… - > ...
->40 - > 40
You want to print numbers from 1 to N so print_numbers(N) can be translated in print_numbers(1, N). 您要打印从1到N的数字,以便可以将print_numbers(N)转换为print_numbers(1,N)。
Now what is print_numbers from X to Y ? 现在从X到Y的print_numbers是什么?
print_numbers from X to Y is print(X) and print_numbers from X+1 to N! 从X到Y的print_numbers是print(X),从X + 1到N的print_numbers!
In Prolog, you will get : 在Prolog中,您将获得:
print_numbers(N) :-
print_numbers(1, N).
% general case X must be lower than Y
print_numbers(X, Y) :-
X =< Y,
writeln(X),
X1 is X + 1,
print_numbers(X1, Y).
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