进度条Python

Question

I've got the following piece of code:

def progressbar(count, total, status=""):
    bar_len = 40
    filled_len = int(round(bar_len * count / float(total)))

    percents = round(100.1 * count / float(total), 1)
    bar = "X" * filled_len + "-" * (bar_len - filled_len)

    print("[{}] {}{} ...{}".format(bar, percents, "%", status),
          end="\r", flush=True)

And for calling the progress bar:

total = 100
i = 0
while i < total:
    i += 1
    progressbar(i, total, status="Creating stuff")
    time.sleep(1)

Where total is a number of iterations. When I run this code I get the progress bar running on multiple lines instead of just one. Any advice?

Answer 1

I don't think you have any issue in your code.

print("[{}] {}{} ...{}".format(bar, percents, "%", status),
          **end="\r"**, flush=True)

the end="\\n" argument in print() method should print the progress bar i one line.

if you run this code in terminal it should work fine.

I have previously seen an issue with PyCharm IDE where end="\\r" doesn't work. It is probably a bug in the terminal emulator in the IDE.

Answer 2

Thanks for everyone that commented on my topic trying to help. I got the solution on another StackOverflow Question: Python 3 progress bar shows nothing

So I tested two ways that were successful. The first one, to print using sys.stdout:

sys.stdout.write("\r[{}] {}{} ...{}".format(bar, percents, "%", status))
sys.stdout.flush()

And the second, using the print() but with the \\r in front of the line:

print("\r[{}] {}{} ...{}".format(bar, percents, "%", status),
      end="", flush=True)

Both works perfectly. The first one needs the import sys.