Python：查找列表中的所有元素是否相同（除了两个数字）

Question

我想知道如何检查两个数字列表是否相同，但恰好是两个数字

if list1 == list2: # + except 2 numbers

Answer 1

def differ_by_two(l1, l2):
    return sum(1 for i,j in zip(l1, l2) if i!=j) == 2

Example

>>> differ_by_two([1,2,3],[1,4,5])
True
>>> differ_by_two([1,2,3,4,5],[6,7,8,9,10])
False

Answer 2

If order of list elements is important, you can use something like this:

if sum(i != j for i, j in zip(list1, list2)) == 2:
    # the two lists are equal except two elements

If order is not important, and repeated elements do not matter, you could also use set intersection ( & ) and compare length:

if len(set(list1) & set(list2)) == len(list1) - 2:
    # the two list are equal except two elements

If order is not important, but repeated elements matter, use the same approach, but with collections.Counter :

from collections import Counter
if len(Counter(list1) & Counter(list2)) == len(list1) - 2:
    # the two list are equal except two elements

Answer 3

def SameBarTwo(l1, l2):
    a = len(l2)
    for i in range(len(l2)):
        if l2[i] in l1:
            l1.remove(l2[i])
            a -= 1
    return a == 2

This will make accommodations for duplicate values, order is not taken into account.