[英]Can't insert data with php into mysql
so i am working on the simple project and i dont know why, but i can't insert data into the database 所以我正在做一个简单的项目,我不知道为什么,但是我不能将数据插入数据库
Here is my connection to database 这是我与数据库的连接
<?php
$servername = "localhost";
$username = "root";
$password = "root";
$database = "register";
// Create connection
$conn = mysqli_connect($servername, $username, $password, $register);
// Check connection
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
echo "Connected successfully";
?>
And in this part of code i am trying to insert data: 在这段代码中,我试图插入数据:
<?php
if (isset($_POST['submitreg'])){
$username = mysqli_real_escape_string($conn, $_POST['username']);
$email = mysqli_real_escape_string($conn, $_POST['email']);
$password = mysqli_real_escape_string($conn, $_POST['password']);
$sql = "INSERT INTO users (email, username, password) VALUES ('$email', '$username', '$password')";
if (mysqli_query($conn, $sql)) {
echo "New record created successfully";
header("Location: signin.php");
} else {
echo "Error: " . $sql . "<br>" . mysqli_error($conn);
}
}
mysqli_close($conn);
?>
And then i am inserting the code, i am getting this error: 然后我插入代码,出现此错误:
Error: INSERT INTO users (email, username, password) VALUES ('gerulisjonas@gmail.com', 'jonas2422', 'password') 错误:向用户(电子邮件,用户名,密码)插入VALUES(“ gerulisjonas@gmail.com”,“ jonas2422”,“密码”)
Thank you in advance :) 先感谢您 :)
extra: Form 额外:表格
<form id="register" class="signinform" action="includes/registerinc.php" method="post">
<div class="formcenter">
<input type="text" name="username" value="" placeholder="user name"><br>
<input type="email" name="email" value="" placeholder="email"><br>
<input type="password" id="passwordid" name="password" value="" placeholder="password"><br>
<input type="password" name="passwordtwo" value="" placeholder="repeat password"><br>
<input type="submit" name="submitreg" class="btn btn-success" value="Register"></input>
</div>
</form>
When creating your connection you named the variable that holds the database name $database
, but when you pass it along to mysqli_connect
you are using $register
. 创建连接时,您将变量命名为持有数据库名称$database
的变量,但是将其传递给mysqli_connect
,则使用的是$register
。
Try this instead: 尝试以下方法:
$database = "register";
// Create connection
$conn = mysqli_connect($servername, $username, $password, $database);
嘿,对不起,我打扰了你,我只是运行我的代码,发现我的register.php文件中没有包含connection.php文件。
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