文字替换挑战（正则表达式）

Question

I can't solve a problem. Perhaps it is impossible to achieve what I want.

GOAL: use only replace function to remove all text except the email address.

I have a text with email in: Start text some other text 2828 text my.address@mail.com some additional text. Regular expression to select email: [a-zA-Z0-9\\-\\._]+@[\\w\\d\\-\\._]+\\.\\w{2,12}

Regular expression works perfectly to find an email address, but it didn't work to remove all letters from an email.

Below print screen shows what I got as a result when apply replace function in the text editor: As results I used regexp .*([a-zA-Z0-9\\-\\._]+@[\\w\\d\\-\\._]+\\.\\w{2,12}).* , and replace it on $1 . Sadly this workflow give me broken email.

I used email as an example, the same result I got for any other data types as URLs, IPs, phones, names, cities, zips etc.

Can anyone unveil a solution to this problem? Thank you a lot.

PS I am not interested in using math() function, because of this function isn't presented in most of the text editors.

Answer 1

I think you should make the first part non greedy .*? or else the .* will match upon the @ and after that just giving up 1 match to satisfy the character class [a-zA-Z0-9\\-\\._]+

If it is not greedy it will capture my.address@mail.com instead of s@mail.com

.*?([a-zA-Z0-9\\-\\._]+@[\\w\\d\\-\\._]+\\.\\w{2,12}).*

Answer 2

I would do it like this:

Find: (.*?)[a-zA-Z0-9\\-\\._]+@[\\w\\d\\-\\._]+\\.\\w{2,12}\\s?(.*?)

Replace: $1$2

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Input: Start text some other text 2828 text my.address@mail.com some additional text

Output: Start text some other text 2828 text some additional text