在PHP中将值传递给JavaScript函数

Question

 while ($row= mysqli_fetch_assoc($result)) { echo "<tr>"; echo "<td>" . $row["madh"] . "</td>"; ..... echo "<td><input type='button' onclick='detail()' value='d'></td>"; echo "</tr>"; } function detail(data){} 

i want to pass $row["madh"] to detail() but I have problem with "" and ''.

Answer 1

虽然这不是最佳选择，但是您可以尝试将回声线分成不同的部分

echo "<td><input type='button' onclick='detail(" . $row["madh"] . ")' value='d'></td>";

Answer 2

put Id here

echo "<td id="id_madh">" . $row["madh"] . "</td>";

when you click on button as in your code

echo "<td><input type='button' onclick='detail()' value='d'></td>";

you can get value using jquery like this

function detail(){
var value_madh = $('#id_madh').val();
}

Answer 3

I think you just need to escape the quotes?

echo "<td><input type='button' onclick='detail($row[\"madh\"])' value='d'></td>";

note that the function will be immediately involved on page load, you probably want to wrote this within a closure so it's not actually invoked until it's clicked:

echo "<td><input type='button' onclick='function(){ detail($row[\"madh\"]) }' value='d'></td>";

Answer 4

First put $row["madh"] in a variable;

$var = $row["madh"];

then

  echo "<td><input type='button' onclick='detail(&#39;$var&#39;)' value='d'></td>";