转义为SPARQL中转换为URI的字符串

Question

Is there a simple way to escape a string in SPARQL when it is to be converted to a URI?

For instance, a string with "1 < 2" could be converted to "1%20%3C%202" .

I suppose a long series of calls to the REPLACE function could do it, following the pattern BIND(REPLACE(?string, '<', '%3C') AS ?escaped) ?

Answer 1

There is a function ENCODE_FOR_URI :

ENCODE_FOR_URI("1 < 2") => "1%20%3C%202"

Specification: https://www.w3.org/TR/sparql11-query/#func-encode