用PHP中的isset（）替换array_key_exists（）

Question

Knowing the differences of array_key_exists() and isset() in PHP, I see a lot of advocates on the web suggesting for replacing array_key_exists() with isset() , but I am thinking is it safe to do so?

In one project, I have the value of $var submitted by users. The value can be anything, even NULL or not set at all. I want to use !empty($var) to check if $var holds a non-empty value, but I understand that using !empty($var) alone is dangerous since if $var isn't pre-defined, PHP will throw an error.

So I have isset($var) && !empty($var) for checking whether $var holds a non-empty value.

However, things get complicated when I have a value stored in an assoc array. Compare the followings, assuming array $arr always exists but the key foo may or may not exist in $arr .

// code snipplet 1
$arr = array();
echo isset($arr['foo']);

// code snipplet 2
$arr = array();
echo array_key_exists('foo', $arr) && !is_null($arr['foo']);

Code snipplet 2 will always work but it seems clumsy and harder to read. As for code snipplet 1 , I had bad experience... I wrote something like that before in the past on a development machine. It ran fine, but when I deployed the code to the production machine, it threw errors simply because key didn't exist in array. After some debugging, I found that the PHP configs were different between the development and the production machines and their PHP versions are slightly different.

So, I am thinking is it really that safe to just replace array_key_exists() with isset() ? If not, what can be of better alternatives of code snipplet 2 ?

Answer 1

In one project, I have the value of $var submitted by users.

How does that work? Users shouldn't be able to set variables . They should be able to, eg, submit form values which end up in $_POST . I repeat, they should not be able to directly create variables in your scope .

If "users" here means some sort of plugin system where people write and include PHP code… then you may want to think about defining a more stable interface than setting variables.

The value can be anything, even NULL…

Not if it's a value submitted through HTTP. HTTP has no concept of null . It's either an empty string or doesn't exist at all.

using !empty($var) alone is dangerous since if $var isn't pre-defined, PHP will throw an error

That is wrong. empty specifically exists to test a variable against false without throwing an error. empty($var) is the same as !$var without triggering an error if the variable doesn't exist.

So I have isset($var) && !empty($var) for checking whether $var holds a non-empty value.

See Why check both isset() and !empty() . (Spoiler: it's redundant.)

 echo isset($arr['foo']); echo array_key_exists('foo', $arr) && !is_null($arr['foo']); 

These both do exactly the same thing. isset returns true if the value exists and its value is not null . The second line returns true if the array key exists and its value is not null . Same thing.

I had bad experience...

You'd need to be more detailed about that, since there should be no caveat to isset as you describe it.

See The Definitive Guide To PHP's isset And empty and Difference between isset and array_key_exists .