Java缩写后用String中的空格替换新行

Question

Whenever I find an abbreviation within a sentence (like Mr., prf. and so on) I would like to delete the '\\n' character at the end of each sentence that contains an abbreviated word. Any ideas are welcome. INPUT OUTPUT

My idea so far is:

List<String> pres = Arrays.asList("dl","Dl", "Prf", "Ing");
for(int i=1;i<4;i++){
    if (z.contains(pres.get(i)))
        f=z.indexOf(pres.get(i));
    z.replaceFirst("\\n"," ");//how i can use my f here to get rid of next new line...?
}

Answer 1

Here is an approximate solution, without knowing the full list of abbreviations which you want to check. You may search on the following pattern, and replace with the first capture group:

((?:Mr|Mrs|Dr)\.[^.]+\.)\n

This will identify the last abbreviation in any sentence which ends in dot immediately followed by a \\n newline. Note that in cases with more than one abbrevation in a single sentence, it would only match the last abbreviation.

String input = "Here is a sentence.  Said Mrs. Canopoy, here is another sentence about Mr. Potato Head.\r\nHere is a third sentence.";
System.out.println(input);
input = input.replaceAll("((?:Mr|Mrs|Dr)\\.[^.]+\\.)\\r\\n", "$1");
System.out.println(input);

Demo

I only check for Mr. , Mrs. , or Dr. , but you may add as many abbreviations as you want to the alternation.

Answer 2

Just use this:

String s = "Mike and Mr.\nDave take dinner.\nThat is very important.\nMe and Ing.\nMike bla bla..";
s = s.replaceAll("(Mr.|Ing.)\n", "$1 ");