java替换数组的元素
[英]java replacing elements of an array
问题描述
The main question will be at the bottom.<\/i>
主要问题将在底部。<\/b> From the text file below, lets say the first integer is a, second is b, and third is c and so forth.<\/i>从下面的文本文件中，假设第一个整数是 a，第二个是 b，第三个是 c，依此类推。<\/b> the program takes a,b and c, parses them, puts them into myCalculations method which returns a string with two integers.<\/i>该程序获取 a、b 和 c，解析它们，将它们放入 myCalculations 方法中，该方法返回一个带有两个整数的字符串。<\/b> The string is parsed, a and b are replaced the integers in said returned string, then the next iteration of the loop will take the new values for a and b, and integer d.<\/i>解析字符串，将 a 和 b 替换为所述返回字符串中的整数，然后循环的下一次迭代将采用 a 和 b 的新值以及整数 d。<\/b> This will continue until the end where a and b are printed to the user.<\/i>这将一直持续到将 a 和 b 打印给用户的末尾。<\/b><\/p>
The input from a two text files is as follows:<\/i>来自两个文本文件的输入如下：<\/b><\/p>
The format of the text file is as follows:<\/i>文本文件的格式如下：<\/b><\/p>
200 345
36
45
36
21
1 个解决方案
解决方案1
0 2018-05-28 12:25:52
I honestly haven't understood what the whole exercise should do, but the code You enlighted could be wrong due to the indexes You use: those indexes are always 0 and 1, even if cycles are performed through some other indexes.老实说，我不明白整个练习应该做什么，但是由于您使用的索引，您启发的代码可能是错误的：这些索引始终是 0 和 1，即使循环是通过其他一些索引执行的。 At the end of the second code snippet, the f-for modify the array "newResults" at the increasing index "f", but that array is read always at the same index: 0 and then 1. So, if "f" gets higher values than "1" then the "aliveSoldiers"'s elements are left unchanged.在第二个代码片段的末尾，f-for 在增加的索引“f”处修改数组“newResults”，但该数组总是在相同的索引处读取：0 和 1。所以，如果“f”得到高于“1”的值，则“aliveSoldiers”的元素保持不变。
In particular, aliveSoldiers is modified only on the first two indexes, the other indexes are not used at all.特别是，aliveSoldiers 仅在前两个索引上进行了修改，其他索引根本没有使用。
Do you need a stack-like or queue-like behaviour?您需要类似堆栈或类似队列的行为吗？
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