在Notepad ++中使用正则表达式进行IPv4地址搜索

Question

I am trying to sanitize a configuration file in notepad++. Basically, I need to find and replace the IPv4 address with regular expression and replace only first two octet, I tried with following regular expression to search for IPV4, however didnt work in notepad++

\b(25[0-5]|2[0-4]\d|1\d\d|[1-9]?\d)(.(?1)){3}\b

Could anyone please help ?

Answer 1

Your regex \\b(25[0-5]|2[0-4]\\d|1\\d\\d|[1-9]?\\d)(.(?1)){3}\\b captures the first octet in group 1, then matches the 2nd and 3rd octet and captures the fourth octet in group 2.

To replace the first 2 octets you want to match the first 2 octets and capture the last 2 octets to keep them in the replacement.

What you could do it to match all 4 octects using (?:25[0-5]|2[0-4]\\d|1\\d\\d|[1-9]?\\d) for an octet and capture the last 2 including the leading dot for the third octet and the replace with XX followed by capturing group 1.

Find

\\b(?:25[0-5]|2[0-4]\\d|1\\d\\d|[1-9]?\\d)\\.(?:25[0-5]|2[0-4]\\d|1\\d\\d|[1-9]?\\d)(\\.(?:25[0-5]|2[0-4]\\d|1\\d\\d|[1-9]?\\d)\\.(?:25[0-5]|2[0-4]\\d|1\\d\\d|[1-9]?\\d))\\b

Replace with

XX\\1