如何从python中的包导入所有函数？

Question

I have a directory as such:

python_scripts/
     test.py
     simupy/
          __init__.py
          info.py
          blk.py

'blk.py' and 'info.py are modules that contains several functions, one of which is the function 'blk_func(para)'.

Within '__init__.py' I have included the following code:

import os
dir_path = os.path.dirname(os.path.realpath(__file__))

file_lst = os.listdir(dir_path)
filename_lst = list(filter(lambda x: x[-3:]=='.py', file_lst))
filename_lst = list(map(lambda x: x[:-3], filename_lst))
filename_lst.remove('__init__')

__all__ = filename_lst.copy()

I would like to access the function 'blk_func(para)', as well as all other functions inside the package, within 'test.py'. Thus I import the package by putting the following line of code in 'test.py':

from simupy import*

However, inorder to use the function, I still have to do the following:

value = blk.blk_func(val_param)

How do I import the package simupy, such that I can directly access the function in 'test.py' by just calling the function name? ie

value = blk_func(val_para)

Answer 1

Pretty easy

__init__.py :

from simupy.blk import *
from simupy.info import *

---

Btw, just my two cents but it looks like you want to import your package's functions in __init__.py but perform actions in __main__.py .

Like

__init__.py :

from simupy.blk import *
from simupy.info import *

__main__.py :

from simupy import *

# your code
dir_path = ....

---

It's the most pythonic way to do. After that you will be able to:

• Run your script as a proper Python module: python -m simupy
• Use your module as library: import simupy; print(simupy.bar()) import simupy; print(simupy.bar())
• Import only a specific package / function: from simupy.info import bar .

For me it's part of the beauty of Python..