我有将信息从SQL Server下拉到下拉框中的PHP表单。 我希望将框中的特定项目作为默认选中

Question

This code is pulling from DB table, and need it to display Information & Tecnology SVCS - 41515 as the default:

    echo '<option value=" ' . $row['department']. '"' . ($row['department'] == "INFORMATION & TECHNOLOGY SVCS -41515") ? ' selected="selected"' : "".'>'.$row['department']. '</option>';

This Code will give me the drop down but not a selected define item: echo ''.$row['department']. '';

Department:

    <?php

    $sql = "SELECT department FROM Department";
    $query = sqlsrv_query($conn,$sql);
            $query_display = sqlsrv_query($conn,$sql);
    while($row=sqlsrv_fetch_array($query_display,SQLSRV_FETCH_ASSOC))
    {
        //echo '<option value=" '. $row['department'].' ">'.$row['department']. '</option>';
        echo '<option value=" ' . $row['department']. '"' . ($row['department'] == "INFORMATION & TECHNOLOGY SVCS -41515") ? ' selected="selected"' : "".'>'.$row['department']. '</option>';
        continue;
    }
    ?>
    </select>
</td>

Answer 1

Put parentheses around the conditional expression, because operator precedence is not what you're expecting.

    echo '<option value=" ' . $row['department']. '"' . (($row['department'] == "INFORMATION & TECHNOLOGY SVCS -41515") ? ' selected="selected"' : "").'>'.$row['department']. '</option>';

To make it easier to read, I usually use a separate variable:

if ($row['department'] == "INFORMATION & TECHNOLOGY SVCS -41515") {
    $selected = ' selected="selected"';
} else {
    $selected = "";
}
echo '<option value=" ' . $row['department']. '"' . $selected .'>'.$row['department']. '</option>';

Answer 2

($row['department'] == "INFORMATION & TECHNOLOGY SVCS -41515")

There was a spacing issue. Needed to be

($row['department'] == "INFORMATION & TECHNOLOGY SVCS - 41515")