正则表达式查找所有字符串和介于两者之间的任意字符的链接

Question

I've a text extract like this (the original text is very long with hyperlinks staggered across):

... <div> <a href=\n=3D"https://www.wonder.com/alerts/remove" style=3D"text-decoration:none;color:#427fed">Unsu=\nbscribe</a> <span style=3D"padding:0px 4px 0px 4px;color:#252525">|<a href=3D"https:=\n//www.wonder.com/url?rct=3Dj&amp;sa=3Dt&amp;></span> =\n<a href=3D"https://www.wonder.com/alerts?source=3Dalertsmail&amp;hl=3Den&=\namp;gl=3DIN&amp;msgid=3DMTA2MzYwOTAxMTQ5NzI4MTc3MTE" style=3D"text-decorati=\non:none;color:#427fed"> View all your alerts </a> </div> </td> </tr> <tr> <=\ntd style=3D"padding:6px 10px 0px 0px;font-family:Arial"> <a href=3D"https:/=\n/www.wonder.com/alerts/feeds/065638/93686812" styl=\ne=3D"text-decoration:none;color:#427fed">...

I'm trying to extract this hyperlink (not necessarily the last one): https:/=\\n/www.wonder.com/alerts/feeds/065638/93686812

I do not know where the '=' will appear in the link. So tried to use a positive lookahead like this:

re.match(r'(?=\\=)\\"https(.*).*\\"', text)

This did not help. Suggestions pls.

Also, is there a way we can define a list where the strings are present and then match a string that has all these strings? I saw couple of posts on matching any in the list, not all. I tried to look for a pattern like (https)&(wonder)&(alerts)&(feeds) but not much luck.

Answer 1

Hi use this regex.

    https:(.*?)(>|")

You can test your regex online in this link I test your text with my regex and got 4 matchs.

Answer 2

这为我工作：

(\"https([^\"])*\d+\")