当包含特定类时，在DOM中隐藏元素
[英]Hide an element in DOM when specific class included
问题描述
I need to hide a div from DOM when specific class included in middle of the html code. 
当html代码中间包含特定类时，我需要从DOM中隐藏div。 Please take a look at this example. 请看这个例子。
<body>
<div class="first-group">
<h1>Hello world</h1>
</div>
<div class="wrapper">
<div class="second-group">
<div class="main">
<div class="small">
<span class="text-block">Hello mars</span>
</div>
</div>
</div>
</div>
</body>
I tried to achieve this with jQuery .closest() but no luck. 我试图用jQuery .closest()实现这一点，但是没有运气。
$( ".text-block" ).closest( ".first-group" ).css( "color", "red" );
Any solution? 有什么办法吗？
5 个解决方案
解决方案1
1 2018-05-31 05:35:37
if($(".second-group span").hasClass("text-block")) { $('.first-group').css('display', "none"); }
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <body> <div class="first-group"> <h1>Hello world</h1> </div> <div class="wrapper"> <div class="second-group"> <div class="main"> <div class="small"> <span class="text-block">Hello mars</span> </div> </div> </div> </div> </body>
解决方案2
1 2018-05-31 05:40:33
Simply if the length of .text-block inside the wrapper is greater then 0 then simply make .first-group display: none . 如果包装器内.text-block的长度大于0，则只需简单地使.first-group display: none 。
if($( ".wrapper" ).find( ".text-block" ).length > 0){ $('.first-group').css( "display", "none" ) }
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <div class="first-group"> <h1>Hello world</h1> </div> <div class="wrapper"> <div class="second-group"> <div class="main"> <div class="small"> <span class="text-block">Hello mars</span> </div> </div> </div> </div>
If you have multiple .first-group and .wrapper then you can simply loop the wrapper and find its parent and previous element of that parent. 如果您有多个.wrapper .first-group和.wrapper则只需循环包装器并找到其父级和该父级的上一个元素。
$( ".wrapper" ).find( ".text-block" ).each(function() { $(this).parents('.wrapper').prev('.first-group').css( "display", "none" ); })
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <div class="first-group"> <h1>Hello world</h1> </div> <div class="wrapper"> <div class="second-group"> <div class="main"> <div class="small"> <span class="text-block">Hello mars</span> </div> </div> </div> </div> <div class="first-group"> <h1>Hello world</h1> </div> <div class="wrapper"> <div class="second-group"> <div class="main"> <div class="small"> <span class="text-block">Hello mars</span> </div> </div> </div> </div>
解决方案3
1 2018-05-31 05:44:15
Your basic problem is that closest() looks for an ancestor. 您的基本问题是， closest（）寻找祖先。 .text-block is not a descendant of .first-group . .text-block不是.first-group的后代。 Use prev() to find the previous sibling of the containing block. 使用prev（）查找包含块的上一个同级。
In response to your comment prevAll works if there are intermediate siblings.根据您的意见， 如果有中间兄弟姐妹，则 prevAll可以使用。I've added a few empty divs to the example to demonstrate.我在示例中添加了一些空的 divs进行演示。I need to check some fringe cases. 我需要检查一些附带情况。
To get this a bit more robust I've used prevUntil to limit the sibling selection combined with prev to find the actual element of interest. 为了使此功能更强大，我使用了prevUntil来限制同级选择，并结合prev来查找实际感兴趣的元素。
$( ".text-block" ).closest( ".wrapper" ).prevUntil(".first-group").prev().hide();
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <body> <!-- This Won't Show --> <div class="first-group"> <h1>Hello world</h1> </div> <div></div><div></div> <div class="wrapper"> <div class="second-group"> <div class="main"> <div class="small"> <span class="text-block">Hello mars</span> </div> </div> </div> </div> <!--This Will Show--> <div class="first-group"> <h1>Hello world, Again</h1> </div> <div></div><div></div> <div class="wrapper"> <div class="second-group"> <div class="main"> <div class="small"> <span class="not-text-block">Hello jupiter</span> </div> </div> </div> </div> <!-- This Won't Show --> <div class="first-group"> <h1>Hello world</h1> </div> <div></div><div></div> <div class="wrapper"> <div class="second-group"> <div class="main"> <div class="small"> <span class="text-block">Hello mars</span> </div> </div> </div> </div> <!--This Will Show--> <div class="first-group"> <h1>Hello world, Again</h1> </div> <div></div><div></div> <div class="wrapper"> <div class="second-group"> <div class="main"> <div class="small"> <span class="not-text-block">Hello jupiter</span> </div> </div> </div> </div> </body>
NOTE this will break if you change your HTML structure. 注意如果您更改HTML结构，这将中断。
解决方案4
1 2018-05-31 05:45:18
The use of closest will only look for its ancestor, while .first-group is outside the .wrapper div. 当.first-group在.wrapper div之外时，最接近的使用只会寻找其祖先。
In the below code, we are finding the ancestor of the element and then use prev() to get previous element with class .first-group 在下面的代码中，我们找到元素的祖先，然后使用prev（）获取类为.first-group的前一个元素
$(this).closest("div.wrapper").prev(".first-group").css('display', 'none');
See if it works. 看看是否可行。
解决方案5
1 2018-05-31 06:07:12
You can try with parents() and siblings() like the following: 您可以尝试使用parents()和siblings() ，如下所示：
$(".text-block").parents('.wrapper').siblings('.first-group').css( "color", "red" );
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <body> <div class="first-group"> <h1>Hello world</h1> </div> <div class="wrapper"> <div class="second-group"> <div class="main"> <div class="small"> <span class="text-block">Hello mars</span> </div> </div> </div> </div> </body>
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