[英]Android Kotlin - How to extend ConstraintLayout?
I'd like my ConstaintLayout to carry extra additional properties, but I have trouble extending it. 我希望ConstaintLayout带有额外的其他属性,但是我很难扩展它。 More precisely I have trouble putting correct constructor into
更准确地说,我在将正确的构造函数放入时遇到了麻烦
class myCL(): ConstraintLayout(???) {
}
To make sure you don't get any quirks in behavior, you should implement it like this. 为了确保您在行为上没有任何怪异,您应该像这样实现它。
class myCL: ConstraintLayout {
constructor(context: Context) : super(context)
constructor(context: Context, attrs: AttributeSet?) : super(context, attrs)
constructor(context: Context, attrs: AttributeSet?,
@AttrRes defStyleAttr: Int) : super(context, attrs, defStyleAttr)
}
The constructor you really need is the one with all arguments: 您真正需要的构造函数是带有所有参数的构造函数:
class myCL(context: Context?, attrs: AttributeSet?, defStyleAttr: Int) :
ConstraintLayout(context, attrs, defStyleAttr) {
}
if you want to implement all three constructors without much hassle you can use @JvmOverloads
and use sensible defaults. 如果要轻松实现所有三个构造函数,则可以使用
@JvmOverloads
并使用明智的默认值。
class myCL @JvmOverloads constructor(context: Context, attrs: AttributeSet? = null, defStyleAttr: Int = 0) : ConstraintLayout(context, attrs, defStyleAttr) {
}
see https://developer.android.com/reference/android/support/constraint/ConstraintLayout 参见https://developer.android.com/reference/android/support/constraint/ConstraintLayout
You can also do something like this to restict to only one super
call -- 您也可以这样做,只打一个
super
电话-
class MyConstraintLayout: ConstraintLayout {
constructor(context: Context) : this(context, null)
constructor(context: Context, attrs: AttributeSet?) : this(context, attrs, -1)
constructor(context: Context, attrs: AttributeSet?, @AttrRes defStyleAttr: Int) : super(context, attrs, defStyleAttr)
}
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