如何使用Windows窗体中的参数打开多个文件

Question

I know how to open an external application within a windows forms application and a file using an argument. Is there a way to pass multiple argument to open more than one file at a time. At the moment file2 simply overwrites file1. Im using Visual Studio 2017 windows forms C#, thanks.

                    ProcessStartInfo startInfo = new ProcessStartInfo();
                    startInfo.FileName = (app + ".exe");
                    startInfo.Arguments = file1;
                    startInfo.Arguments = file2;
                    Process.Start(startInfo);

Answer 1

It very much depends on the application you're launching. Does it support opening multiple files via command line? You would have to check its command line arguments.

If you made the other application, you can pass multiple arguments to the Arguments property by separating them with spaces. Note that you'll also have to put them in quotes if there are spaces in their paths.

So to launch the application you would do something like this:

ProcessStartInfo startInfo = new ProcessStartInfo();
startInfo.FileName = (app + ".exe");
startInfo.Arguments = string.Format("\"{0}\" \"{1}\"", file1, file2);
Process.Start(startInfo);

and then in the other application, you have your Main method:

public static void Main(string[] args)
{
     // args[0] contains file1
     // args[1] contains file2
}