C＃中的条件类型参数

Question

I would like to deserialize object into a given class type, depending on whether the ajax response was successful or not.

So I written the following method:

public IAjaxResponse GetResponse<TOk, TFail>()
{
    var responseJson = this.response as Dictionary<string, object>;

    object obj = null;

    if ((string)responseJson["status"] == "ok")
        obj = JsonConvert.DeserializeObject<TOk>(responseJson);
    else
        obj = JsonConvert.DeserializeObject<TFail>(responseJson);

    return (IAjaxResponse)obj;
}

Now it's pretty straightforward to use:

var response = GetResponse<ClassWhenOk, ClassWhenFail>();
if (response is ClassWhenFail responseFail) {
    Error.Show(responseFail.message);
    return;
}
[..]

---

Now my problem is : sometimes, there are generic responses which happend to be always 'ok' status so I don't want to use the second type argument for failed status.

So I would want to use something like that:

               \/ notice one type argument
GetResponse<ClassWhenOk>();

This is not allowed though since using this generic method requires 2 type arguments.

So here comes my question :

Can I somehow mark the second type argument ( TFail ) as 'not required'? Or should I rather go for different approach?

Answer 1

Your code just doesn't make sense. The responseJson object cannot be a Dictionary<string, string> and a string at the same time. It would be good to be able to post real code for us to work from.

Here's a refactored example that does compile, but needs some work to behave properly at run-time. Nevertheless, all you need is an alternative overload to make this work.

public IAjaxResponse GetResponse<TOk, TFail>(string response)
{
    var responseJson = new Dictionary<string, object>();

    object obj = null;

    if ((string)responseJson["status"] == "ok")
        obj = Newtonsoft.Json.JsonConvert.DeserializeObject<TOk>(response);
    else
        obj = Newtonsoft.Json.JsonConvert.DeserializeObject<TFail>(response);

    return (IAjaxResponse)obj;
}

public IAjaxResponse GetResponse<TOk>(string response)
{
    return (IAjaxResponse)Newtonsoft.Json.JsonConvert.DeserializeObject<TOk>(response);
}

The second method could even be this:

public IAjaxResponse GetResponse<TOk>(string response)
{
    return GetResponse<TOk, FailDontCare>(response);
}

That just avoids code duplication.