[英]Skip special characters while converting ASCII to HEX in C
I need help to get the ascii to hex data output only for alphanumeric characters(excluding special characters). 我需要帮助以仅将字母数字字符(不包括特殊字符)的ascii转换为十六进制数据输出。
Input String is: 86741-30011
Expected result is: 38363734313330303131
Actual Result is: 3836373431
Output breaks after non alphanumeric characters. 输出在非字母数字字符后中断。 It contains output string only until non alphanumeric characters.
它仅包含输出字符串,直到非字母数字字符为止。
Code: 码:
int main(void){
char word[12] = { '8', '6','7','4','1','-','3','0','0','1','1'};
char outword[20];
int i, len;
len = strlen(word);
printf("Input string: %s\n", word);
//printf("Total length: %d\n", len);
if(word[len-1]=='\n') word[--len] = '\0';
for(i = 0; i<len; i++) {
if (isalnum(word[i]) == 0) {
printf("%c is not an alphanumeric character.\n", word[i]);
} else {
sprintf(outword+i*2 , "%02X", word[i]);
}
}
printf("Hex output:%s\n", outword); return 0;
}
Can anyone help me to get expected output? 谁能帮助我获得预期的输出?
Thanks in advance. 提前致谢。
Use different variables for loop rotation and adding data into array. 使用不同的变量进行循环旋转并将数据添加到数组中。
#include <stdio.h>
int main(void){
char word[12] = { '8', '6','7','4','1','-','3','0','0','1','1'};
char outword[20];
int i, j, len;
len = strlen(word);
printf("Input string: %s\n", word);
//printf("Total length: %d\n", len);
if(word[len-1]=='\n') word[--len] = '\0';
for(i = 0,j=0; i<len; i++) {
if (isalnum(word[i]) == 0) {
printf("%c is not an alphanumeric character.\n", word[i]);
} else {
sprintf(outword+j*2 , "%02X", word[i]);
j=j+1;
}
}
printf("Hex output:%s\n", outword); return 0;
}
This code will give you the expected result 38363734313330303131. 该代码将为您提供预期的结果38363734313330303131。
You need to count input and output position separately. 您需要分别计算输入和输出位置。
for(i = 0; i<len; i++)
{
if (isalnum(word[i]) == 0) {
printf("%c is not an alphanumeric character.\n", word[i]);
} else {
sprintf(outword+i*2 , "%02X", word[i]);
}
}
If your condition is true and you print the text, the counter i
is incremented. 如果您的条件为真并且您打印文本,则计数器
i
会递增。 This is not only used to get to the next in-character, but also do define the position in output-array. 这不仅用于到达下一个字符,而且还定义了输出数组中的位置。 This means the 2 bytes in the out-array are not touched while you parse the input.
这意味着在解析输入时不会触及数组外的2个字节。
If by accident you have 0 bytes there, your string is terminated here. 如果偶然在此处有0个字节,则字符串在此处终止。
This would lead to the following layout: "3836373431\\0\\03330303131"
which is printed as "3836373431"
. 这将导致以下布局:
"3836373431\\0\\03330303131"
打印为"3836373431"
。
You might add another variable for output and only increment when you really convert to hex. 您可以为输出添加另一个变量,并且仅在真正转换为十六进制时才递增。
int outpos;
for(i = 0, outpos = 0; i<len; i++)
{
if (isalnum(word[i]) == 0) {
printf("%c is not an alphanumeric character.\n", word[i]);
} else {
sprintf(outword+outpos*2 , "%02X", word[i]);
outpos++;
}
}
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