网址解析问题：排除“ +”号

Question

I have a URL

viberpa://aafff+a@viber.com?phone_number=vv+9nc3pVg==&user_id=cc+9nc3pVg==

when I tried with the following sample code for parsing the URL

//input code
const url = require("url");
 let uri = 'viberpa://aafff+a@viber.com?phone_number=vv+9nc3pVg==&user_id=cc+9nc3pVg==&token_created_time=2018-05-28T11:31:42.760Z'
 let uri_pasrse = url.parse(uri, true);
 console.log(uri_pasrse.query);

getting query strings:

{ phone_number: 'vv 9nc3pVg==',
  user_id: 'cc 9nc3pVg==',
  token_created_time: '2018-05-28T11:31:42.760Z' }

the query strings are excluded the + symbol. How can I get the original query strings using parsing method or suggest any alternative method?

Answer 1

Each query parameter must be encoded previously. In javascript (NodeJS in this case) you can use encodeURIComponent:

'use strict';

const url = require('url');
const uri = `viberpa://aafff+a@viber.com?phone_number=${encodeURIComponent('vv+9nc3pVg==')}&user_id=${encodeURIComponent('cc+9nc3pVg==')}&token_created_time=2018-05-28T11:31:42.760Z`;
const uri_parse = url.parse(uri, true);
console.log(uri_parse.query);

Result:

{ 
    phone_number: 'vv+9nc3pVg==',
    user_id: 'cc+9nc3pVg==',
    token_created_time: '2018-05-28T11:31:42.760Z'
}