在卡片列表中选择一个以上的随机物品

Question

I want to have two separate random selections from the same list. Is there any way to do this that doesn't include making separate lists?

import random


cards = [2,3,4,5,6,7,8,9,10,'King','Queen','Jack']
cards = random.choice(cards)

suits = ['Clubs', 'Hearts', 'Spades', 'Diamonds']
suits = random.choice(suits)

first_card = ("your first card is the {} of {}") .format(cards,suits)
second_card = ("your second card is the {} of {}") .format(cards,suits)

print first_card
print second_card

Output

your first card is the 10 of Spades
your second card is the 10 of Spades

I want the output to be the same but the last card dealt is different from the first; two separate cards

Answer 1

Beforehand, generate all cards from figures and suits, by example with a list-comprehension. Then use random.sample to pick two random cards.

import random

figures = [2, 3, 4, 5, 6, 7, 8, 9, 10, 'King', 'Queen', 'Jack']
suits = ['Clubs', 'Hearts', 'Spades', 'Diamonds']

cards = [(figure, suit) for figure in figures for suit in suits]

print(random.sample(cards, 2)) # [(5, 'Hearts'), (7, 'Diamonds')]

Although, I recommend you do not mix integers and strings to define your figures as this may lead to some confusion. I recommend you assign integers 11 , 12 and 13 to Jack , Queen and King respectively.

Answer 2

you can use itertools to generate all combination and then shuffle the list and take two , I have designed function for n_samples you can select n no of samples:

import random
import itertools

cards = [2,3,4,5,6,7,8,9,10,'King','Queen','Jack']


suits = ['Clubs', 'Hearts', 'Spades', 'Diamonds']

def n_random(list_1,list_2,no_of_samples):
    all_possible=[i for i in itertools.product(list_1,list_2)]
    if no_of_samples>len(all_possible):
        return 'Wrong choice'
    else:
        random.shuffle(all_possible)
        return all_possible[:2]

print(n_random(cards,suits,2))

output:

[(3, 'Diamonds'), (2, 'Spades')]

Answer 3

Use random.sample .

random.sample(population, k) :

Return a k length list of unique elements chosen from the population sequence or set.

import random

cards = [2,3,4,5,6,7,8,9,10,'King','Queen','Jack']
chosen_cards = random.sample(cards,2)

suits = ['Clubs', 'Hearts', 'Spades', 'Diamonds']
chosen_suits = random.sample(suits,2)

first_card = ("your first card is the {} of {}") .format(chosen_cards[0],chosen_suits[0])
second_card = ("your second card is the {} of {}") .format(chosen_cards[1],chosen_suits[1])

print(first_card)
print(second_card)

Answer 4

This guarantees a different card every time:

from random import randint
cards = [2,3,4,5,6,7,8,9,10,'King','Queen','Jack']
first_card = cards[randint(0, len(cards)-1)]
second_card = cards[randint(0, len(cards)-1)]
while second_card == first_card:
   second_card = cards[randint(0, len(cards)-1)]
print first_card
print second_card