从指定的索引列表python之外的字符串中删除所有字符

Question

I have two strings:

strA='EEEEEE     HHHH      HHHHHHH' 

and string B of equal size

strB='AJKFKKJSNCKSJNFKSJASLOINCLAJ'

I want to create a third string strC which only has the characters in strB corresponding to a given character in strA .

For example I am interested in position of characters in strB corresponding to 'H' in strA , the output should look like:

strC='           SJNF      OINCLAJ'

with the gaps intact.

I tried this:

def find(s, ch):
    return [i for i, ltr in enumerate(s) if ltr == ch]

temp= find(strA,'H') The output is:

temp= [11, 12, 13, 14, 21, 22, 23, 24, 25, 26, 27]

when I tried creating a new string, str_new by doing the following:

str_new = strB[temp]

I get an error

How do I do this?

Answer 1

You can use zip :

strA='EEEEEE     HHHH      HHHHHHH' 
strB='AJKFKKJSNCKSJNFKSJASLOINCLAJ'
strC = ''.join([' ' if b != 'H' else a for a, b in zip(strB, strA)])

Output:

'           SJNF      OINCLAJ'