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如何在Swift中为URL编码大型数据对象?

[英]How do I encode a large Data object for a URL in Swift?

I want to open my iOS application using a URL but my url appears to be too long? 我想使用URL打开我的iOS应用程序,但是我的URL似乎太长了? Is there a limit on the length of the URL? URL的长度有限制吗? I've searched the web all day on this and it looks like there is no definitive answer. 我整天都在网上搜索此内容,但似乎没有确切的答案。 My url contains a base64EncodedString of an object and is about 1,500 bytes. 我的网址包含一个对象的base64EncodedString,大约1,500个字节。

It looks like this: 看起来像这样:

MyApp://favorite?Class=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

I want to text or email this URL and then have the recipient tap on the link to open my app on their device. 我想通过短信或电子邮件发送该URL,然后让收件人点击链接以在其设备上打开我的应用。

The trouble is the link is wrapped in the mail and messages application and only the "MyApp://favorite?" 问题在于链接被包装在邮件和消息应用程序中,只有“ MyApp:// favorite?”包装。 part is marked in blue as a link. 零件以蓝色标记为链接。 The remainder of the text is not part of the link. 其余文本不属于链接。

Is there any way to send data like this via a URL? 有没有办法通过URL发送这样的数据?

This doesn't sound like it has anything to do with the URL itself or Swift. 听起来这与URL本身或Swift没有任何关系。 The problem you're describing is with "the mail and messages application." 您正在描述的问题与“邮件和消息应用程序”有关。 It sounds like you're sending the message in plaintext and relying on the data detector to find it. 听起来您好像是在以纯文本形式发送消息,并且依赖于数据检测器来找到它。 That's asking too much of the data detector, which is a heuristic guessing process. 这对数据检测器的要求很高,这是一种启发式猜测过程。 If you want to make it as a link, you should send it as an HTML mail, and mark it with <a href> . 如果要使其成为链接,则应将其作为HTML邮件发送,并用<a href>标记。

Some notes on the format, though: 不过,有关格式的一些注意事项:

This data is double-base64-encoded, which is very wasteful. 此数据是双base64编码的,非常浪费。 If you only encoded one time, this would be: 如果您只编码一次,则将是:

MyApp://favorite?Class=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

which saves over 350 bytes over your current approach. 与您目前的方法相比,可节省350多个字节。

If you run this through gzip before Base64-encoding it, it'd be a third of this size (~550 bytes). 如果在对Base64进行编码之前通过gzip运行它,则它将是该大小的三分之一(约550字节)。 And using a binary format, you could probably get this down to ~200 bytes (after base64-encoding) without even getting clever. 并且使用二进制格式,您可能甚至可以将它压缩到200个字节左右(在进行base64编码之后),甚至不会变得更聪明。

That said, URLs are perfectly capable of handling data of this size. 也就是说,URL完全能够处理这种大小的数据。 I suspect your problem is just asking heuristic systems to detect the URL rather than marking exactly where it is with HTML. 我怀疑您的问题只是要求启发式系统检测URL,而不是使用HTML精确标记出URL。

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