[英]How can I convert a JSON string of objects into an ArrayList using Gson?
So I have a JSON string of countries like this: 所以我有一个像这样的国家的JSON字符串:
{
"details": [
{
"country_id": "1",
"name": "Afghanistan",
"regions": null
},
{
"country_id": "2",
"name": "Albania",
"regions": null
},
{
"country_id": "3",
"name": "Algeria",
"regions": null
},
... and so on
}
Now I want to have a method that tries to convert this into an ArrayList
of countries. 现在我想要一个方法, 试图将其转换为国家的
ArrayList
。
public static ArrayList<GFSCountry> get() {
return new Gson().fromJson(countriesJson, new TypeToken<ArrayList<GFSCountry>>(){}.getType());
}
But I get an 但我得到了一个
Expected BEGIN_ARRAY but was BEGIN_OBJECT at line 1 column 2 path
As per request, here is my GFSCountry
class: 根据要求,这是我的
GFSCountry
类:
@SerializedName("country_id")
@Expose
private String countryId;
@SerializedName("name")
@Expose
private String name;
@SerializedName("regions")
@Expose
private Object regions;
public String getCountryId() {
return countryId;
}
public void setCountryId(String countryId) {
this.countryId = countryId;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public Object getRegions() {
return regions;
}
public void setRegions(Object regions) {
this.regions = regions;
}
I know I should adjust something either from the JSON string or the method. 我知道我应该从JSON字符串或方法调整一些东西。 Any help?
有帮助吗?
Since the list is nested in your JSON you will need a small mapping class that contains the list. 由于列表嵌套在JSON中,因此需要一个包含列表的小型映射类。
Try 尝试
static class GFSCountryList {
public List<GFSCountry> details;
}
public static List<GFSCountry> get() {
return new Gson().fromJson(countriesJson, GFSCountryList.class).details;
}
It seems to me that Gson is expecting your json to be like this 在我看来,Gson期待你的json是这样的
[
{
"country_id": "1",
"name": "Afghanistan",
"regions": null
},
{
"country_id": "2",
"name": "Albania",
"regions": null
},
{
"country_id": "3",
"name": "Algeria",
"regions": null
},
... and so on
]
But it encounters an object (marked by { }) 但它遇到一个对象(用{}标记)
Either you have the possibility to change your json format, or you create a class with a "details" attribut as a list to be compatible with the json's format. 要么你有可能改变你的json格式,要么创建一个带有“details”的类作为列表,以便与json的格式兼容。
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