[英]remove object from array if property value match
I have array of objects that look like: 我有一系列看起来像的对象:
{
"brandid": id,
"brand": string,
"id": id,
"categoryId": id,
"category": string,
"factory": string,
"series": string,
"status": 0,
"subStatus": 1
}
if the series property value matches another series property value in the other objects in the array, that object needs to be removed from the array. 如果series属性值与数组中其他对象中的另一个series属性值匹配,则需要从数组中删除该对象。
Currently I have attempted to push them to a duplicate Array with : 目前,我尝试使用以下命令将它们推送到重复的数组:
const seriesResCopy = seriesRes;
const dupArray = []
for (const thing of seriesResCopy) {
for (const item of seriesRes) {
if (thing.series === item.series) {
dupArray.push(item);
}
}
}
but this does not work. 但这不起作用。 From examples I have seem my issue has been that I do not have a definite list of duplicate values to look for.
从示例看来,我的问题似乎是我没有要查找的重复值的明确列表。
Any help would be much appreciated. 任何帮助将非常感激。
You could use a Set of series to filter out duplicates: 您可以使用一系列序列来过滤出重复项:
const exists = new Set();
seriesRes = seriesRes.filter(({series}) => !exists.has(series) && exists.add(series));
This uses: Array.prototype.filter
, Object destructuring and some logical tricks. 它使用:
Array.prototype.filter
,对象解构和一些逻辑技巧。
The same can be done by mutating the array: 可以通过更改数组来完成此操作:
const exists = new Set();
for(const [index, {series}] of seriesRes.entries()) {
if(!exists.has(series) {
exists.add(series);
} else {
seriesRes.splice(index, 1);
}
}
To filter duplicates from the array and keep the first instance: 要从数组中过滤重复项并保留第一个实例:
let seriesWithoutDuplicates = seriesRes.filter((s, i, self) => {
return self.findIndex(z => z.series === s.series) === i;
});
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